Warning!!!!

[vapspaz]

Do NOT do a google search for CE4+.

It will make your head hurt.

My god does my little head hurt from reading this crap. And I just have to ask myself why? Why didn't you just close that page and move on dumbazz.


1. Write down oxidation reaction of 1 mole of Cr(NCS)6(4-)knowing that all N goes into NO3(-), all C goes into CO2, all S goes into SO4(2-) and chromium changes oxidation state to +3. Since it is acidic medium, you can put either H(+) or H2O to the left part of equation. H(+) won't help you to balance oxygens, but H2O will (do not forget to put H(+) to the right now):
Cr(NCS)6(4-)+54H2O-xe -->Cr(3+) + 6NO3(-) + 6CO2 + 6SO4(2-) + 108H(+). Now, the number x of electrons that were transfered from Cr(NCS)6(4-) can be determined if you equalize the total charge of the left and right parts of the equation:
-4-x*(-1)=3+6*(-1)+6*(-2)+108*(+1)
x=97
So, first half of the equation will look like this:
Cr(NCS)6(4-)+54H2O-97e -->Cr(3+) + 6NO3(-) + 6CO2 + 6SO4(2-) + 108H(+).
Second half is very simple: Ce(4+) +1e --> Ce(3+)
Multiply the second half by 97 and combine both halves:

Cr(NCS)6(4-)+54H2O+97Ce(4+) --> 97Ce(3+)+Cr(3+) + 6NO3(-) + 6CO2 + 6SO4(2-) + 108H(+).



This has been a public safety message from your local dumbazz Vapspaz.

 

[Briar]

Thanks, I was just about to do the search!

Do NOT do a google search for CE4+.

It will make your head hurt.

My god does my little head hurt from reading this crap. And I just have to ask myself why? Why didn't you just close that page and move on dumbazz.


1. Write down oxidation reaction of 1 mole of Cr(NCS)6(4-)knowing that all N goes into NO3(-), all C goes into CO2, all S goes into SO4(2-) and chromium changes oxidation state to +3. Since it is acidic medium, you can put either H(+) or H2O to the left part of equation. H(+) won't help you to balance oxygens, but H2O will (do not forget to put H(+) to the right now):
Cr(NCS)6(4-)+54H2O-xe -->Cr(3+) + 6NO3(-) + 6CO2 + 6SO4(2-) + 108H(+). Now, the number x of electrons that were transfered from Cr(NCS)6(4-) can be determined if you equalize the total charge of the left and right parts of the equation:
-4-x*(-1)=3+6*(-1)+6*(-2)+108*(+1)
x=97
So, first half of the equation will look like this:
Cr(NCS)6(4-)+54H2O-97e -->Cr(3+) + 6NO3(-) + 6CO2 + 6SO4(2-) + 108H(+).
Second half is very simple: Ce(4+) +1e --> Ce(3+)
Multiply the second half by 97 and combine both halves:

Cr(NCS)6(4-)+54H2O+97Ce(4+) --> 97Ce(3+)+Cr(3+) + 6NO3(-) + 6CO2 + 6SO4(2-) + 108H(+).



This has been a public safety message from your local dumbazz Vapspaz.

 

[JesByChance]

LOL!! That just made my day!

 

[badkolo]

we arent bothering with the ce4+ at the moment, the stardust is made form a different company and we will stick with what we tested out to be better

remeber how we skipped the ce3?

 

[vapspaz]

Sounds good to me bro. I'm just getting confused with all these new names folks are tossing around and trying to figure out what is what thus the google search mistake. LOL

Now if y'all would just get those Stardust back in stock so I could try them I'd be a happy camper.

 

[cement]

Multiply the second half by 97 ??? I think someone pulled that number out of their rear end, that cant be right !!!

 

[wolf1959]

No, the 97 is correct, but I am not sure about that changing the oxidation state to + 3; that just doesn't sound right,...

Sent from an alternate reality using my Droid

 

[vapspaz]

LMAO! I was hopping some one other than me caught those mistakes.

 

[zoiDman]

LMAO! I was hopping some one other than me caught those mistakes.

You weren’t in Equilibrium but it didn’t want to say anything. Or at least I don't think you were.



Hey my thing was Hard Core Mathematics when I did my Under Graduate work. But if there was one thing I Remember in Chemistry, besides that the girl with the short skirt who wanted to sit next to me who was Smoking Hot, was Equilibrium.

 

[Secti0n31]

I ordered one of the ego fitting ce4's from one of yer competitors just to try it. Considering I love ego batts and ce2 type cartos I figure why not? However in light of that I had to cut myself off after my last GV purchase until the next paycheck. This last run should have me with 6 tanks, 5 new 30ml bottles of juice in addition to the 300ish ml I currently have, a ce4+, a VV mod in the shop and 4 working ego's (2 genuine at 3.4v, two knockoffs at 3.7v). Not to mention the handfulls of boge and ce2 cartos, or all of the cr123 batteries.

Compared to the crap we vapers do/buy/learn/tweak, that oxidation reduction titration chemical reaction should be child's play.