16w will draw power 2x faster than 8watts.. Kinda think of it as drinking with a big straw vs a small straw. The amount of drink in the cup might be the same. (Amperage). But the effort and rate, to drain the cup might be different.
What drains a battery faster, Volts or Amps?
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16w will draw power 2x faster than 8watts.. Kinda think of it as drinking with a big straw vs a small straw. The amount of drink in the cup might be the same. (Amperage). But the effort and rate, to drain the cup might be different.
But 20 watts into 1 ohm will draw less current from the battery than 20 watts into 3 ohms.
This is due to the mod having to convert the battery voltage to a higher voltage to get 20 watts in the 3 ohm load.
This is due to the mod having to convert the battery voltage to a higher voltage to get 20 watts in the 3 ohm load.
No.
20 watts into 1 ohm will require 4.5 amps at 4.5 volts from the output of the regulated mod;
meanwhile the battery may be supplying the 20 watts as 5 amps at 4 volts.
Simple answer... battery life is measured in mAh... that is how many milli-amps it is capable of discharging for 1 continuous hour. Robert is absolutely correct. How fast a battery drains is a direct correlation to how many amps the device draws.
The simplest answer to your question... it's all about airflow. With the right amount of airflow, you can comfortably vape a very hot build...
The simplest answer to your question... it's all about airflow. With the right amount of airflow, you can comfortably vape a very hot build...
Yeah... Doesn't a Regulated Mod's Battery always output the Same Voltage? ei: Whatever the Voltage of the Battery is at any Given Moment.
I did specify battery vs mod.
so YES, not no.
the voltage output form a regulated mod is not the battery voltage. It is converted using a combination of Buck/boost and or PWM or pulsed DC circuitry to achieve the desired wattage.
At wattages requiring less than the battery voltage the mod will either regulate the voltage down or more often pulse the DC voltage on and off to get the desired wattage.
At wattages requiring a higher voltage than the battery voltage the ?Buck/Boost circuitry will boost the battery voltage up to get the desired wattage. this buck boost circuitry has some loss so it will use more watts from the battery than at a lower voltage output from the mod.
I am a lifelong Electronics tech and have designed Buck/boost circuits.
They all have some loss ie more watts in than out.
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1: On a regulated mod the Output Voltage of the Battery is usually somewhere between 3 volts and 4.2 volts.
The Output Voltage of the regulated mod is different from the Output Voltage of the battery.
Nope the regulated mod will boost the battery output voltage as needed to get the desired watts you want into the atomizer at whatever the resistance of it's coil is.
this is why the drain of the battery will often be higher than the watts output of the regulated device.
Regulated egos are an exception as they only put out 3.7 volts or whatever till their battery voltage drops below that point.
The twist style Ego's work the same as the regulated mods however using buck/boost circuitry to boost the battery voltage up to 4-6 volts.
There are also regulated vs unregulated stick batteries ie 808.
Not saying that the Regulated Mod doesn't change the Batteries Voltage to achieve whatever the Users has set the Mod Output for.
What I am saying is that the Voltage Output of the Mods Battery is not Changed. It is whatever the current Voltage is for any given time.
So when I put a Fresh Battery into my Regulated Mod, the Battery Output starts off at say 4.2 Volts. And the Battery Voltage falls slightly every time I push the Power Button.
You said:
" 20 watts into 1 ohm will draw less current from the battery than 20 watts into 3 ohms."
20 watts into 1 ohm will draw 5 amps from the battery if the battery is 4 volts.
The voltage accross the 1 ohm will be 4.5 volts and
the current through the 1 ohm will be 4.5 amps.
20 watts into 3 ohm will draw 5 amsp from the battery if the battery is 4 volts.
The voltage accross the 3 ohm will be 7.7 volts and
the current through the 3 ohm will be 2.6 amps
20 watts into 1 ohm draws the same 5 amps from the battery as 20 watts into 3 ohms.
What you are thinking about is the 4.5 amps going through the 1 ohm coil and the 2.6 amps going through the 3 ohm coil.
You are not taking into account the losses inherent in the circuitry used to boost the actual battery voltage up to 7.7 volts.
It is minimal but it is there.
Yep the voltace control and conversion circuitry is between the actual battery and the atomizer. And the efficiency of this converter/control circuit is where some of the wattage/power is lost and why the ucrrent draw from the battery will not always be the same as the current the mod puts out.
yep I would say that is a fair range for them. As I said the difference is negligable but it is there.
Yep esp with the higher wattage ones they would cook themselves at lower efficiencies.
It is also why they have automatic high temp shutdown. Solid state devices tend to act like lithium cells in that if they get to a critical temperature they go into thermal runaway and destroy themselves.
Yeah... Heat is a Good Sign the Law of Conservation of Energy is still working. LOL
Haven't really followed all Chip-Sets with regards to Efficient. But here are 2 Boards that I did remember seeing their Efficiency...
http://www.evolvapor.com/datasheet/dna30.pdf
http://www.evolvapor.com/datasheet/dna40.pdf
Yep so the DNA 30 loses 6% of the energy/watts/amps the battery puts out and converts it to heat in the circuitry.
So if the DNA 200 is the same efficiency it eats up 12 watts at full output power so the battery is actually providing 212 watts not 200.
yet another reason to provide a bit of headroom on your battery ampacity limit for safety.
So if the DNA 200 is the same efficiency it eats up 12 watts at full output power so the battery is actually providing 212 watts not 200.
yet another reason to provide a bit of headroom on your battery ampacity limit for safety.
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