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Zener Diode or more specifically, a TVS Diode. .68-.72ohms with an output of roughly 4.8-5.5v is roughly what you want.
A zener diode is used to provide a reference voltage. It cannot be used by iself as a voltage reducing power supply!
Using a zener dode
A zener diode provides a good way to achieve a stable lowered voltage but requires a power tansistor or mosfet to handle the load current. The zener diode is used in reverse; it has a specific voltage drop used this way (forwards it works like a normal diode).
Basically the zener sets the base voltage of the transistor and there will be a further drop of about 0.6V
through the transistor, so to get say 4.5V out the zener required qould be 4.5+0.6 = 5.1V (some transistors have a lower forward drop than 0.6v);
Example circuit using a power zener diode with a power transistor:
http://sound.westhost.com/appnotes/an007.htm
See also:
http://nptel.iitm.ac.in/courses/Web...uits/lecturers/lecture_27/lecture27_page3.htm
Using power diodes (easy solution)
Modern power diodes have a 0.35V forward drop (some versions might be 0.7v). Such as the 1N4001. Just connect these in series to drop the voltage the required amount (3 of them to drop by just over 1V). These diodes are robust - no danger from connecting the wrong way, simply no current flow.
Using a voltage regulator (fairly easy solution)
Input voltage needs to be about 1.5V higher than the output (check specifications). Contains a zener and power transistor in one easy-to-use 3 pin package (and perhaps output sensing and comparator for extra stability).
Example:
http://www.electro-tech-online.com/...h-current-power-supply-circuit.html#post80417
(see also the notes below that post)