what kind of diode do I need to lower voltage???

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kinabaloo

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+1 ...

Zener Diode or more specifically, a TVS Diode. .68-.72ohms with an output of roughly 4.8-5.5v is roughly what you want.

A zener diode is used to provide a reference voltage. It cannot be used by iself as a voltage reducing power supply!

Using a zener dode

A zener diode provides a good way to achieve a stable lowered voltage but requires a power tansistor or mosfet to handle the load current. The zener diode is used in reverse; it has a specific voltage drop used this way (forwards it works like a normal diode).

Basically the zener sets the base voltage of the transistor and there will be a further drop of about 0.6V through the transistor, so to get say 4.5V out the zener required qould be 4.5+0.6 = 5.1V (some transistors have a lower forward drop than 0.6v);

Example circuit using a power zener diode with a power transistor:
an007-f1.gif

http://sound.westhost.com/appnotes/an007.htm
See also:
http://nptel.iitm.ac.in/courses/Web...uits/lecturers/lecture_27/lecture27_page3.htm

Using power diodes (easy solution)

Modern power diodes have a 0.35V forward drop (some versions might be 0.7v). Such as the 1N4001. Just connect these in series to drop the voltage the required amount (3 of them to drop by just over 1V). These diodes are robust - no danger from connecting the wrong way, simply no current flow.

Using a voltage regulator (fairly easy solution)

Input voltage needs to be about 1.5V higher than the output (check specifications). Contains a zener and power transistor in one easy-to-use 3 pin package (and perhaps output sensing and comparator for extra stability).

Example:
4419d1113176252-high-current-power-supply-circuit-psu_5v.gif

http://www.electro-tech-online.com/...h-current-power-supply-circuit.html#post80417
(see also the notes below that post)
 
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youfillintheblank

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THAT'S the code I was trying to remember!!! IN4001....I just did a quick search and also found the IN4004, which on the Source's website says somewhere has a voltage drop of .8V which is around what I was aiming for.

Thanks guys, hope this works.

Modern power diodes have a 0.35V forward drop (some versions might be 0.7v). Such as the 1N4001. .
 

Laredo7mm

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Mar 20, 2009
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...I need to lower the voltage on my 6 volt mods...

Go to texas instruments website and search for "UCC383TDKTTT-5" It is a low drop out (LDO) voltage regulator. Max Vin is 9v, Min Vin is 5.45V. Output is fixed at 5V. You want the DDPAK/TO-263 form factor.

I have been using this chip for a month or so with no issues.
 
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Misty

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I know it's in here somewhere, but I can't find it. I need to lower the voltage on my 6 volt mods, I am going through too many atomizers. I know there is some name or type to the diode that will lower voltages in a DC circuit by .7v or so. Anybody know that one??
Nuck used this diode (1N4001) - he posted on this thread
http://www.e-cigarette-forum.com/fo...93-nuked-hell-out-my-atmoizer.html#post282078


edit: took too long to post!- I see Kinabaloo posted the same diode
 
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Laredo7mm

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Mar 20, 2009
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...has a voltage drop of .8V which is around what I was aiming for...quote]

.8v drop is alot for a 6 volt source. What happens when the voltage in the batteries drops to 5V? Then you are only sending 4.2 volts to the atomizer. I assume you are using CR2 batteries. If you change to CR123a batteries that have a nominal voltage of 3.7 and max of 4.2 and put them in series, and then use the chip I mentioned in my previous post, you will have quite a nice set up.

I am using two 18350 batteries with the TI LDO regulator. Works great. 18350's are shorter versions of 18650's.
 
Go to texas instruments website and search for "UCC383TDKTTT-5" It is a low drop out (LDO) voltage regulator. Max Vin is 9v, Min Vin is 5.45V. Output is fixed at 5V. You want the DDPAK/TO-263 form factor.

I have been using this chip for a month or so with no issues.

A good suggestion :)

For a small voltage drop and with limited space, the 1N4001 diodes are ideal (small and robust). For a more professional solution the voltage regulator is simple and also robust.

For more examples of electronic circuits of all kinds, see:
http://www.e-cigarette-forum.com/fo...-electronics-resource-modders.html#post286125
 
...has a voltage drop of .8V which is around what I was aiming for...quote]

.8v drop is alot for a 6 volt source. What happens when the voltage in the batteries drops to 5V? Then you are only sending 4.2 volts to the atomizer.

But the diode will still be supplying power. The voltage regulator may well switch off.

The voltage regulator is best suited to sources other than batteries.
 
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