been beating around in the back of my mind as well gummy...
The specs say "Up to 12 W Output Power". Whining means it's starved for current. The battery needs more ooph. And remember you are boosting, so if the atty wants 2.5A the battery will have have to provide more than that depending on the voltage/boost, I'm surprised Gummi isn't having problems with that high resistance UF batt. But we don't know what resistance/amps/watts he's at.
As an example to get 8W @ 4.4V you need about 1.8A. For that 8W the 3.7V cell would need to output about 2.2A (I think that's right).
One quick question though. Seeing as the native output is 5V, if vaping at 4.4V, through the use of a diode, should these AMP/watts calculations actually be calculated at 5V?That's right. Power in = power out + losses. So, using 90% efficiency and 8W output as an example, input power is 8W/.9 or 8.9W. If battery voltage is 3.7V, that would be 2.4 amps input..
It's hard to say and you won't find that way mentioned in the datasheet.Vo to Rset? How does that work?
I'm not questioning that it works to cut the native voltage. I'm just saying it's not listed in the datasheet.I don't know why it works, but it does! Gummy told me to do it that way, said he didn't remember where he got it from, I'll take Willy B's word for it since he's been around here longer than me. I'm using the chip, as Gummy says "nekkid" no caps or diode with an IMR 26650 and it takes a couple of days for the batt to get down to 3.5v. I'm very happy with it.