I ran across this article describing TSNAs in mainstream tobacco smoke and am having trouble understanding how the quantities compare to the
the quantity in njoy vapor. Only one of the 4 types found in the liquid (quantity of 8 ng/g total) is present in the vapor. "ANALYZE's best estimate was that the concentration of NAT in the aerosol samples were 2 - 5 ng/L (i.e.,detectable, but not reliably quantifiable). NNN, NAB, and NNK were not detected." Document available at: http://www.casaa.org/files/Study_TSNAs_in_NJOY_Vapor.pdf
Now that's expressed as nanograms per Liter. That's a very, very teensy amount, right?
This abstract talks about mg/L (milligrams per Liter) in mainstream smoke, ranging from 0.5 to 100.
It looks as if 1 mg is a heck of a lot of nanograms. I found an online converter and plugged the lower end of the range, "0.05" into the mg. field and the answer came up 500,000 nanograms. That seems to be a much bigger number than a range of 2 to 5 nanograms of NAT in vapor.
Vapor:
2 to 5 nanograms per Liter (only NAT is present)
Smoke:
500,000 to 100,000,000 nanograms per Liter (all 4 are present)
Am I looking at this correctly? Is the comparison of the high end of the two ranges really 20 million to 1?
the quantity in njoy vapor. Only one of the 4 types found in the liquid (quantity of 8 ng/g total) is present in the vapor. "ANALYZE's best estimate was that the concentration of NAT in the aerosol samples were 2 - 5 ng/L (i.e.,detectable, but not reliably quantifiable). NNN, NAB, and NNK were not detected." Document available at: http://www.casaa.org/files/Study_TSNAs_in_NJOY_Vapor.pdf
Now that's expressed as nanograms per Liter. That's a very, very teensy amount, right?
This abstract talks about mg/L (milligrams per Liter) in mainstream smoke, ranging from 0.5 to 100.
SpringerLink - Journal ArticleAbstract An improved method was developed for the determination of the four major tobacco-specific nitrosamines(TSNAs) in mainstream cigarette smoke. The new method offers decreased sample preparation and analysis time as compared to traditional methods. This method uses isotope dilution liquid chromatography coupled with a tandem mass spectrometer with electrospray ionization and is significantly more sensitive than traditional methods. It also shows no evidence of artifactual formation of TSNAs. Sample concentrations were determined for four TSNAs in mainstream smoke using two isotopically labeled TSNAs analogues as internal standards. Mainstream smoke was collected on an industry standard 44-mm Cambridge filter pad, extracted with 0.1 mol/L ammonium acetate, purified by solid-phase extraction, and analyzed without further sample cleanup. The analytical column is a 3.9 mm × 150 mm Waters Symmertry Shield RP18 column and volume fraction of the mobile phase is 50% methanol, 50% water containing 0.1% acetic acid. The results show that the linear range is 0.5–100.0 mg/L except for N-nitrosoanabasine (NAB) from 0.25 to 50.0 mg/L. The limits of detection are 0.1 mg/L for N-nitrosonornicotine (NNN), 0.08 mg/L for 4-(methylnitrosamino)-1-(3-py-ridyl)-1-butanone (NNK), 0.05 mg/L for N-nitrosoanatabine (NAT) and 0.06 mg/L for NAB. The recoveries of the four TSNAs are from 90.2% to 105.7%.
It looks as if 1 mg is a heck of a lot of nanograms. I found an online converter and plugged the lower end of the range, "0.05" into the mg. field and the answer came up 500,000 nanograms. That seems to be a much bigger number than a range of 2 to 5 nanograms of NAT in vapor.
Vapor:
2 to 5 nanograms per Liter (only NAT is present)
Smoke:
500,000 to 100,000,000 nanograms per Liter (all 4 are present)
Am I looking at this correctly? Is the comparison of the high end of the two ranges really 20 million to 1?
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