Batteries for Vamo

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SoundlessHero

Full Member
Mar 1, 2013
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Emeryville
They are all '18650' mate, but it's the ****mAh which gives the power so to speak:2cool:

Two stacked, unprotected high drain 18350's = starting output voltage of around 8.3-8.6V
One single unprotected, high drain 18650 = starting output voltage of around 4.1-4.2V

The power dissipated by a resistor (the coil): P = V^2/R:

a 3.0 ohm coil will get:

P = (8.3^2)/3.0 = 22.963 W - Two 18350's
P = (4.1^2)/3.0 = 5.063 W - One 18650

These number change immediately when you hit the button because it is dependent on Buck/Boost circuitry!

but draw is what we want: W = V*I

W = 3.7V * 700 mAh = ~2.6 Watt Hours * 2 cells = about 5.2 watthours avalaible
W = 3.7V * 2200 mAh = ~8.1 Watt Hours

Now the 18650 is superior since it will supply 3.7V stored longer at load.

Of course, I recommend trying both configurations in conjunction with what you find to be your ideal vape including the resistance coil, wicking system and VV/VW. You have to factor in all those, since once you have your system set up, as soon as you hit the button and start vaping, all these above numbers change ;)
 
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