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Lower resistance coils use more watts, and hence amps, at any given voltage. So if you have an unregulated device, a lower ohm coil will drain the battery proportionately faster than a higher ohm coil will.

On a VV device, that's true if you use the same voltage for both resistances. If you adjust for flavor, you're probably matching the wattage pretty well, so the drain is the same.

On a VW device, the voltage will adjust to keep the wattage the same and the battery drain speed is pretty much identical no matter what ohm resistance you use.

Mind you, plenty of other variables come into play--that's in a perfect world. There are efficiency differences when bucking and boosting, which can change the map a little bit.
 

Chef Geoff

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Feb 22, 2013
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Ok thanks...wasn't sure if LR attys were delivering more watts at the coil with the same amount of volt output, or if the LR was just making the battery work harder....been killing my first VV very quickly no matter the ohm coil and wasn't sure why...I figured all watts had to come from the batt at the end of the day, but thought it was worth asking anyway
 
Ok thanks...wasn't sure if LR attys were delivering more watts at the coil with the same amount of volt output, or if the LR was just making the battery work harder....been killing my first VV very quickly no matter the ohm coil and wasn't sure why...I figured all watts had to come from the batt at the end of the day, but thought it was worth asking anyway

LR atties do deliver more watts at the coil for a given voltage, which does make the battery work harder (put out more energy). A 1,000 mAh battery, which averages 3.7 volts, contains 3.7 watts of power.

If you're vaping it at 7.4 watts, you'd get about half an hour out of the battery (if the transition is perfect, which it usually isn't).

Vaping at 5 watts, you'd get about 45 minutes.

For simple stuff (like resistors), it's pretty easy.

Raise the watts, you either have to raise the volts or the amps (or both)
Lower the watts...you get the idea.

Or, W=VA (Watts = Volts * Amps)
V = IR (Volts = Amps * Resistance) (Yeah, they use I here just to be confusing, I think!)

So therefore:

W = IRA. Since I = A:

W = A*A*R (Watts = Amps-squared times Resistance)

Or:

W = (V*V)/R (Watts = Volts-squared divided by Resistance)
(because W = VA and A = V/R)
 
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