I just love all the equations, and "Exact" methods presented here
JW,
here's a "seat of the pants" analysis of the eGo output

1) unloaded cell voltage is in the order of 4.2 volts (the Li-ion cell on the inside), agree?
2) the instantaneous peak loaded voltage from the cell,
through the magic circuitry, and driving a 2.0 ohm carto is between 3.9 and 3.7. Anyone not believe that? Would 3.8VDC +/- 0.1v be a reasonable assumption?
Why not 4.2 volts to the carto as peak?
3) the magic circuitry of the eGo generates a pulsed dc waveform with a rather high Duty Cycle. Agree still?
4) Knowing peak voltage (3.8 +/- 0.1) we can "Calculate" the RMS voltage for duty cycles ranging from 80% to 100%. Agree?
5) Knowing the squarish shape of the waveform, peak voltage, we can calculate Average voltage for that Duty Cycle range. Agree?
6) We can calculate the percentage difference for each of the hypothetical RMS values and Average values. Agree?
7) The percentage difference between the RMS and Average values decreases as Duty Cycle goes up. Agree?
8) The Average voltage approaches RMS as the duty cycle approaches 100%. Agree?
Now the questions:
At what duty cycle does the difference between RMS and Average become reasonable for measuring an e-cig (like maybe 3 or 4% percent, or about a tenth of a volt)?
Would the Average voltage from an eGo exceed the RMS value?
What duty cycle would produce an average voltage equal to the RMS value?
The measurement accuracy of the "Cheapo" meter when used to measure RMS voltage output from the eGo is:
A) +/- 50%
B) +/- 10%
C) +/- 3%
D) Better when the eGo is at a partial charge than at full charge.
You guys have fun with your equations
