Decided to try 12mg nicotine...

Status
Not open for further replies.

Iusedtoanalog

Ultra Member
ECF Veteran
Verified Member
Mar 17, 2011
1,197
430
Pennsylvania
Hi Nahoku, Your theory is fairly flawed as I know it to be. Here is why.

1. Kirchoff's voltage law states that the signed sum of the voltage drops around a series circuit is zero. A consequence of this is that the voltages across elements of a parallel circuit must be the same.

2. Ohm's law states that current is voltage divided by resistance. Since the voltage across each new parallel element is the same, the current in that element is known. A consequence of this is that each additional element does not change the current in the other elements.

3. Kirchoff's current law states that the signed sum of the currents entering a node is zero. A consequence of this, and 1 and 2 above, is that the currents added by each parallel element increases the total current entering the set of parallel elements.

In short if the voltage applied is the same across the circuit, and the additional element does not change the current in any other element in the circuit, then in this and every parallel circuit the loads are to be calculated as independant from one another, drawing the same current from the source as if they where alone in the circuit.

The benefit of a dual coil cartomizer is a function of surface area of the coil to the liquid being vaporized, two coils of three ohms(given the same gauge and type of resistance wire) will have double the surface area of that of a single coil cartomizer, I do usedual coil cartos on occasion, and this is not some internet myth being perpetrated by just Me, its also Kirtchoff and that Ohm guy too
 

Worzel

Super Member
ECF Veteran
Jan 3, 2013
870
804
Lakeland, Florida
Okay manilar, you can try a couple of things. The next time you order, get a variety of strengths. Order a bottle of zero, a bottle of 6mg, and a bottle of 12mg. Your needs change as you vape. You can (if your juice vendor allows) order 12mg juice, request extra flavoring, go to Wally World and get a bottle of vegetable glycerine to dilute your juice. Another thing you can do is order 12mg juice unflavored, go to Wally World get some glycerine to dilute, and get some bottles of Lor Ann oil to flavor your juice.
 

Aheadatime

Ultra Member
ECF Veteran
Verified Member
Feb 20, 2013
1,060
756
USA
Main reason why I wanted to try 12mg was because 6mg wasn't satisfying my nicotine needs... haha that sounds bad, but I think my sweet spot would be around 8-10..

I hear ya. I'm the same way. Mornings and nights I enjoy a 9 or 10mg vape, while throughout the day I can settle for 6mg. As others have suggested, simply buy a 6mg and a 12mg of a juice you enjoy, mix them, and you'll have yourself a 9mg.
 

jvail52

Unregistered Supplier
Apr 13, 2013
0
1
fort collins, co
  • Deleted by classwife
  • Reason: Unregistered Supplier - Forum Rules

Iusedtoanalog

Ultra Member
ECF Veteran
Verified Member
Mar 17, 2011
1,197
430
Pennsylvania
[/QUOTE=Cool_Breeze;9244133]Iusedtoalalog - interesting point about the surface area. What about power...watts? Dropping the resistance by a factor of 2 increases the overall current by 2 and thus raises the power by a factor of 2. In a confined area with 2x the power, is surface area the only matter to consider?[/QUOTE]

They too perform as if they where the sole load in the system, because the doubling of amperage causes the whole total system to produce more wattage, but it is shared across the system. This is because the system voltage is constant(both loads see the same voltage and require their own amperage to run within the system), the load in this question is our variable so if we where using a single coil at 3.7v with a load of 3ohms, then we would have the wattage output of 4.5633 , Then our dual coil version at 3.7v with a load of 1.5ohms would have a system power of 9.12667 watts, but because there are two loads who have their own current consumption (as referenced by Kirtchoff,Ohm) they are equally producing half the rated output of the system of 4.5633 each..... In this case you see why the dual coil cartos like to be driven hard into the higher spectrum of voltage. And to follow this why so many folks complain that a dc carto is not performing like the think it should. They are afterall just two three ohm coils. How many people do you know that use a 3ohm carto on 3.7volts and say that it is more than they want? I myself am vaping a 1.9ohm carto right now (and most every day) at 5.2volts........

One of my favorite calculators, also for reference http://www.the12volt.com/ohm/ohmslawcalculators.asp

So Cool Breeze the question of coil area in contact with liquid the only matter to consider, no but the only one of importance to me that would be relevant to the Original Posters question of more throat feeling. She is using a higher nicotine ratio than before and a different carto which can heat/vaporize more eliquid at a faster rate than her previous equipment ..... For me the other factor is battery draw, a subject near and dear to my heart. I do not like putting mass strain on my batteries. I vape alot(~10ml today) so having a device that allows me to vape from when I get up in the morning at about 6am until I get to bed at about 1am without having to charge batteries, take my mod apart, locate fresh batteries, remove charged batteries......... This is the same reason why I own three genesis atties but dont use them as my all day feed device, they are too much load for my personal tastes. This holds true for dual coil cartos(for me) they dont allow me the ability to runn the long runtimes that I personally prefer. To some this is a non-issue, for me its a deal breaker.
 
Last edited:

nahoku

Super Member
ECF Veteran
Verified Member
Mar 5, 2013
554
291
Honolulu, Hawaii
Hi Nahoku, Your theory is fairly flawed as I know it to be. Here is why.

1. Kirchoff's voltage law states that the signed sum of the voltage drops around a series circuit is zero. A consequence of this is that the voltages across elements of a parallel circuit must be the same.

2. Ohm's law states that current is voltage divided by resistance. Since the voltage across each new parallel element is the same, the current in that element is known. A consequence of this is that each additional element does not change the current in the other elements.

3. Kirchoff's current law states that the signed sum of the currents entering a node is zero. A consequence of this, and 1 and 2 above, is that the currents added by each parallel element increases the total current entering the set of parallel elements.

In short if the voltage applied is the same across the circuit, and the additional element does not change the current in any other element in the circuit, then in this and every parallel circuit the loads are to be calculated as independant from one another, drawing the same current from the source as if they where alone in the circuit.

The benefit of a dual coil cartomizer is a function of surface area of the coil to the liquid being vaporized, two coils of three ohms(given the same gauge and type of resistance wire) will have double the surface area of that of a single coil cartomizer, I do usedual coil cartos on occasion, and this is not some internet myth being perpetrated by just Me, its also Kirtchoff and that Ohm guy too

This is why there is so much confusion in this forum. People either don't understand electronics, or simply misinterpret information presented. As much as I won't dispute Kirchoff's law, it simply has no bearing on a simple resistive parallel circuit containing two resistors. If you think you really need to quote Kirchoff's law for a circuit this simple, I don't know what to say!

Let's take this apart...

Going by what you're saying....

In short if the voltage applied is the same across the circuit, and the additional element does not change the current in any other element in the circuit, then in this and every parallel circuit the loads are to be calculated as independant from one another, drawing the same current from the source as if they where alone in the circuit.

In the example I used with parallel 3 ohm resistors, if you take them as separate elements and each element does not affect the other, and is calculated independently... then what is the current in each 3 ohm resistor? ... what is the power dissipated by each 3 ohm resistor?

The current in each is 3.7 / 3 = 1.23 amps. Then the power each dissipates must be (1.23)(1.23)(3) = 4.5 watts.

Now please tell me why you think these calculations are flawed?

The benefit of a dual coil cartomizer is a function of surface area of the coil to the liquid being vaporized, two coils of three ohms(given the same gauge and type of resistance wire) will have double the surface area of that of a single coil cartomizer

If you read my post again, you'll see that I wrote this... "As far as the assumption that more juice is being vaporized by a dual coil cart, I'm still out on that because I can't really tell."

However, going by what you're saying, it appears that your statement is fact. Is it? Can you show me something, a link, or anything that proves that a dual coil cartomizer outputs more vapor than a single coil cartomizer burning at twice the power? I would love to see it.
 

Iusedtoanalog

Ultra Member
ECF Veteran
Verified Member
Mar 17, 2011
1,197
430
Pennsylvania
Hi Nahoku, After reading your initial post a second time due to your numbers in your response I see why I thought you where incorrect. I should have re read it the first time. I missed your 1.5ohm single cartomizer in the jpg image. I never actually opened the image to full size. Then neglected to correlate that in with my response.

Being that you and I are coming up with the same numbers in our calculations for this circuit we are in fact describing the same events.

In your initial post I thought the picture was a single 3ohm carto versus a dual 3ohm carto (and you see how i could think that would look). And that you where saying that the voltage was shared(halved) between the two coils,again my misinterpretation.

Since we are talking about the exact same thing, and explaining our theories with the exact same math, I do believe that we agree with each other. Sorry about misunderstanding what you where saying. But I do feel that a dual coil carto has the ability to vaporize liquid at a faster rate, you just have to drive them unreasonably hard in order to make that a reality. At eGo voltage I feel a single coil carto outperforms a dual coil by a noticeable difference.

Sorry for the misunderstanding. See you around.
 

nahoku

Super Member
ECF Veteran
Verified Member
Mar 5, 2013
554
291
Honolulu, Hawaii
Hi Nahoku, After reading your initial post a second time due to your numbers in your response I see why I thought you where incorrect. I should have re read it the first time. I missed your 1.5ohm single cartomizer in the jpg image. I never actually opened the image to full size. Then neglected to correlate that in with my response.

Being that you and I are coming up with the same numbers in our calculations for this circuit we are in fact describing the same events.

In your initial post I thought the picture was a single 3ohm carto versus a dual 3ohm carto (and you see how i could think that would look). And that you where saying that the voltage was shared(halved) between the two coils,again my misinterpretation.

Since we are talking about the exact same thing, and explaining our theories with the exact same math, I do believe that we agree with each other. Sorry about misunderstanding what you where saying. But I do feel that a dual coil carto has the ability to vaporize liquid at a faster rate, you just have to drive them unreasonably hard in order to make that a reality. At eGo voltage I feel a single coil carto outperforms a dual coil by a noticeable difference.

Sorry for the misunderstanding. See you around.

No problem!
 
Status
Not open for further replies.

Users who are viewing this thread