Do 2 batteries increase Amperage?

[BeginnerOfVaping]

Hello,

I am new to vaping, but got the smok ALIEN 220W kit and put in 2 Samsung 30q batteries.
The kit came with V8 Baby-Q2 Core (0.4Ω dual coils) and V8 Baby-T8 Core (0.15Ω octuple coils).

The Ohm's law calculator showed that the V8 Baby-T8 Core with 0.15Ω needs 24A,
but both batteries have only 15A (20A).
The question is, do 2 batteries increase the Amperage and is it safe to vape from the
V8 Baby-T8 Core?

Thank you.

 

[BeginnerOfVaping]

Hello,

I am new to vaping, but got the SMOK ALIEN 220W kit and put in 2 Samsung 30q batteries.
The kit came with V8 Baby-Q2 Core (0.4Ω dual coils) and V8 Baby-T8 Core (0.15Ω octuple coils).

The Ohm's law calculator showed that the V8 Baby-T8 Core with 0.15Ω needs 24A,
but both batteries have only 15A (20A).
The question is, do 2 batteries increase the Amperage and is it safe to vape from the
V8 Baby-T8 Core?

Thank you.

 

[untar]

You're confusing calculations for mechanical/unregulated with calculations for regulated.
What matters for regulated is at what wattage you're vaping. To stay inside the "safe" zone of 15A CDR of your Samsungs the max power you can use is 75W.

Calculating battery current draw for a regulated mod | E-Cigarette Forum

At what power are you vaping? If it's above 75W you need different batteries. Even at around 70W-75W I'd suggest different batteries since you're riding them pretty hard and don't take advantage of the higher capacity those batteries offer, they perform better at lower wattages.

 

[untar]

Please do not double post, one thread is plenty
Ohm's law and batteries

 

[Rossum]

Ohm's law is not directly applicable to a regulated mod. On a regulated mod, the resistance of the coil(s) is not what determines how much current is being pulled from your batteries. Instead, the amount of power you're telling the mod to apply to the coil(s) is. Let's say you have power set to 90 watts. Add 10% for losses in the regulator circuit and call it 100 watts that the batteries need to supply. Divide that by the number of batteries, so in a dual battery mod, running at 90 watts, each battery must supply 50 watts. Now divide the 50 watts by the cut-off voltage of the mod, call it 3 volts. The result is that each battery needs to supply just shy of 17 amps.

 

[BeginnerOfVaping]

Ohm's law is not directly applicable to a regulated mod. On a regulated mod, the resistance of the coil(s) is not what determines how much current is being pulled from your batteries. Instead, the amount of power you're telling the mod to apply to the coil(s) is. Let's say you have power set to 90 watts. Add 10% for losses in the regulator circuit and call it 100 watts that the batteries need to supply. Divide that by the number of batteries, so in a dual battery mod, running at 90 watts, each battery must supply 50 watts. Now divide the 50 watts by the cut-off voltage of the mod, call it 3 volts. The result is that each battery needs to supply just shy of 17 amps.

Thank you for the answer! This really made me curious. So that basically means I can use the V8 Baby-T8, and I am safe until I increase the recommended 35W-50W per Samsung 30q battery?

 

[BeginnerOfVaping]

You're confusing calculations for mechanical/unregulated with calculations for regulated.
What matters for regulated is at what wattage you're vaping. To stay inside the "safe" zone of 15A CDR of your Samsungs the max power you can use is 75W.

Calculating battery current draw for a regulated mod | E-Cigarette Forum

At what power are you vaping? If it's above 75W you need different batteries. Even at around 70W-75W I'd suggest different batteries since you're riding them pretty hard and don't take advantage of the higher capacity those batteries offer, they perform better at lower wattages.

Thank you for the answer! I am vaping at 65W. What batteries would you recommend for the Alien 220W?

 

[sonicbomb]

The Samsung 30Q or the LG HG2, and don't exceed 120 watts. The mod is not a factor in this, and neither is the coil resistance. Did you read the article untar linked to?

 

[untar]

It depends what kind of power you need. If you want to have a little headroom I'd suggest Sony VTC5A (25A CDR 2500mAh), it's a nice balance of power and capacity. You'd be able to go up to 126W with those (in the Alien, 2.8V low voltage cutoff).
Here's an overview of recommended batteries
Mooch's Recommended Batteries | E-Cigarette Forum

 

[untar]

The mod is not a factor in this

Low voltage cutoff is part of the formula so... yeah it is a factor. In the Alien (2.8V) that means you can go up to 126W with the VTC5A, in a mod with 3.2V low cutoff you can go up to 144W with the same batteries and stay at or below CDR.

 

[sonicbomb]

agreed

 

[Hawise]

Thank you for the answer! I am vaping at 65W. What batteries would you recommend for the Alien 220W?

Samsung 25Rs would also work.

One of our very helpful members, Mooch, had made a chart of recommended batteries. It shows the CDRs of all the batteries he recommends:

Mooch's Recommended Batteries | E-Cigarette Forum

To figure out what CDR you need to vape at a given wattage on a regulated mod, the formula is:

Minimum CDR = Wattage ÷ number of batteries ÷ 3.2 ÷ 0.9

That formula's also from Mooch, who explains it here (and @untar linked to it earlier):

Calculating battery current draw for a regulated mod | E-Cigarette Forum

So for 65 watts on a two battery mod, you need batteries with at least a 12 amp CDR. Your Samsung 30Qs, at 15 amps, are probably fine. A 20 A battery, like the 25R, might be better. Batteries deteriorate with use and with age so it's best to give yourself a fair bit of breathing room. Your batteries will tend to last a lot longer if you do.

Welcome to ECF!

 

[Topwater Elvis]

You wouldn't use 3.2v in calculating battery amp draw when using a power device with a 2.8v low voltage cut off, such as the OP is.

 

[Baditude]

Did the math for you.

WATTAGE PER SINGLE BATTERY on REGULATED MOD:
(Wattage doubles using 2 batteries/triples using 3 batteries)

Up to 45W:

Samsung 18650 30Q, 3000 mah 15 amp CDR

Sony 18650VTC6 3000mAh 15 amp CDR

Up to 60W:

LG 18650HG2 3000mah 20 amp CDR

LG 18650HE4 2500 mah 20 amp CDR

Samsung 18650-25R, 2500 mah 20 amp CDR

Sanyo UR18650NSX, 2500 mah 20 amp CDR

Sony 18650VTC5, 2600 mah 20 amp CDR

Sony 18650VTC4, 2100 mah 23 amp CDR

AW 18650 3000 mah 20 amp CDR

Up to 75W:

LG 18650 HD4 2100 mah 25 amp CDR

LG 18650 HD2 2000 mah 25 amp CDR

Samsung 18650-24S, 2500 mah 25 amp CDR

Sony 18650VTC5A, 2500 mah 25 amp CDR

Up to 90W:

LG18650HB6 1500mah 30 amp CDR

LG18650HB2 1500mAh 30 amp CDR

LG18650HB4 1500mAh 30 amp CDR

Samsung 18650-20S 2000mah 30 amp CDR

 

[Hawise]

You wouldn't use 3.2v in calculating battery amp draw when using a power device with a 2.8v low voltage cut off, such as the OP is.

Thank you, I missed that.

@BeginnerOfVaping, with the 2.8 v cutoff it would be:

65 watts/ 2 (batteries)/ 2.8 v/ 0.9 = 13 a per battery

 

[ScottP]

Two 15 amp batteries can support up to 90 watts. The easiest way to calculate what your batteries can support is this:

Max Watts per battery = Max Battery Amp * 3
Max Watts total = Max Watts per battery * number of batteries.
So in this case:
15A * 3 = 45W max per battery
45W * 2 = 90 W max total.

That is "MAX" possible, but it is NEVER a good idea to run things at max, not to mention as batteries age they will not be able to continue to hit that max. So to that end, I would suggest limiting yourself to about 75W-80W on that mod using those batteries. If you want to go higher, get some 20A-25A batteries.

 

[denali_41]

if they are in series it doubles your voltage
if they are parallel it doubles your amperage

 

[Hawise]

if they are in series it doubles your voltage
if they are parallel it doubles your amperage

While that's true, it doesn't actually affect your battery needs a regulated mod. When voltage is higher, you need fewer amps, while if the voltage is lower, you have more amps available. With a regulated mod it comes down to wattage, battery cutoff and number of batteries, however they may be connected.

 

[ScottP]

if they are in series it doubles your voltage
if they are parallel it doubles your amperage

Close, but not quite. NOTHING doubles the Max Current Discharge Rate of a battery.
The correct statement would be:

If they are in series it doubles your voltage, but capacity (mAh) will not double
If they are parallel it doubles your capacity (mAh) but voltage will not double

 

[Nate5700]

Close, but not quite. NOTHING doubles the Max Current Discharge Rate of a battery.
The correct statement would be:

If they are in series it doubles your voltage, but capacity (mAh) will not double
If they are parallel it doubles your capacity (mAh) but voltage will not double

It wouldn't double the discharge rate of the battery but current will split between the two batteries if they are in parallel. So if each battery supplied 15 amps it would give you 30 amps total.

I wouldn't recommend it though. There can be variations of the internal resistance of the batteries among other factors, so you can't guarantee that current will split equally between batteries in parallel. What we were taught in electrical engineering school was to always put batteries in series and use a regulator.