I was just trying to show, just because the atty dropped 1 milliohm and and the individual coil dropped 2 milliohms, nothing cooled faster than the other because they are the same temperature.
.
I ran the TCR math on some more real world values...
You are right, Spirometry.
I was wrong.
The rise and fall of twice the ohms in the parallel circuit does happen, like I suspected, but like you said, the math of the TCR formula, when paired with parallel resistor math, works out to keep the temperature the same in each coil, between dual and single.
Here's the math for a .15-ohm Ni200 build, with a .1 ohm rise and drop in resistance:
TCR formula:
(Rref + rD) = Rref [1 + a(T - Tref)]
R = resistance at temp T
Rref = resistance at temp Tref
a = TCR
T = temp
Tref = ref temp for the TCR
rD = resistance delta (rise)
Single coil build TCR formula:
(.15 + .1) = .15[1 + .006(T - 20)]
A .1-ohm rise and fall equates to 131.1C, or
267.9F.
For the dual build to read at .15-ohm, each coil needs to be .3-ohm.
So the same .1-ohm rise of the circuit, means each resistor inside it must rise .2 ohm.
Dual coil build TCR formula:
(.3 + .2) = .3[1 + .006(T - 20)]
A .2-ohm rise and fall required for each coil equates to 131.1C, or
267.9F
Well, F. me. I need a vape and some scotch.