Does the length of the wire between joints determine the resistance?

[johnlikestovape]

For example, if I am making a single coil on my Ithaka:

I cut and use 2 inches of 28 awg resistance wire (R) and two 3.5 inches of nonresistance wire (NR) (nonresistance wire will be irrelevant in my question but I figured I'd throw it in there). And since I don't have a wire zapper, I have to twist the the R wire with the NR wire. Now let's say I use .25 inches of R wire to twist with the NR wire on one side AND the other side. This means that I've used .5 inches of R wire to twist with both of my NR wires, leaving me with 1.5 inches of R wire in between the joints.

Now according to my math:
- 2 inches of 28 awg kanthal = .88 ohms
- 1.5 inches of 28 awg kanthal = .66 ohms

Here is where I get a little confused. Is the resistance of my atomizer .88 ohms or .66 ohms? To my understanding, electricity takes the path of least resistance to ground (in our case, the negative 'post'). And since those joints shouldn't be touching any other metal on the Ithaka, the electricity MUST ignore the joints (since they don't lead to ground) and go straight through the coil to get to the negative post. Meaning the resistance of my atomizer is .66 ohms.

Is my logic correct? Or will the atomizer's resistance still be .88 ohms because that's the amount of resistance wire in the device?

*****I am ignoring other factors like internal resistance, resistance of the nonresistance wire, etc. and just looking strictly at the resistance wire.

Thanks for your help!
-John

 

[justinred]

.66 ohms. Resistance ends where you joined the NR and R wire.

 

[johnlikestovape]

@justinred Thought so! Thanks man I appreciate it.

 

[tobarger]

justinred is right
Resistance = Length of resistance wire between the two twisted joints

 

[Aal_]

I realized something the other day. I was dry burning my single coil, and i saw the part where the join is, is lighting up. That join was long but never the less it shouldn't be lighting up, the interesting thing is that you see the resistance wire lighting up in between the non resistance wire. If it is, then it should count against the resistance no?

 

[tobarger]

Yes it counts but its not significant

 

[imeothanasis]

it was only a matter of a bad join aal

I realized something the other day. I was dry burning my single coil, and i saw the part where the join is, is lighting up. That join was long but never the less it shouldn't be lighting up, the interesting thing is that you see the resistance wire lighting up in between the non resistance wire. If it is, then it should count against the resistance no?