Don't forget about Watts Law

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beckdg

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I am not talking about a chip that fails I am talking about ones that instead of doing proper step down act like a mech in not allowing the device to go lower than the voltage in the cells.
That's a topic for a specific device, not a topic relevant to regulated mods in general.

Tapatyped
 
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suprtrkr

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Absolutely not.

The circuitry can buck or boost the voltage output through it while only getting the voltage provided from the cell. This skews the resistance seen by the battery to a resistance determined by the completed circuit. The whole circuit resistance will differ from the coil resistance nearly 100% of the time in a regulated device.

Tapatyped
Just so. Resistance is fixed (ignoring thermal flux and TCR in the conductors) in the circuits on both sides of the board, but they are usually not equal. Nor do they have to be.
 
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beckdg

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I have been saying this(watts law) since the day I joined and all it does is get me into arguments
I have no idea why people with reg mods are so fixated on ohms and actually once had someone who had been a memeber for quite a while ask me what you need watts law for...so the question gained from this is....how have people with reg mods been calculating amp draw on their batts???
They come here and ask what batts to buy.

Which, I, personally consider just as well if they're going to stick to regulated devices.

I wouldn't expect you to become a mechanic to drive your vehicle. And let's be honest, an overworked, massive, exploding battery in your face could very easily be the least of your worries.

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beckdg

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Just so. Resistance is fixed (ignoring thermal flux and TCR in the conductors) in the circuits on both sides of the board, but they are usually not equal. Nor do they have to be.
The battery doesn't see 2 fixed resistances and a variable voltage regulator. The battery sees a circuit with 1 resistance that changes according to user setting and battery output voltage.

That's what I was referring to.

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suprtrkr

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The battery doesn't see 2 fixed resistances and a variable voltage regulator. The battery sees a circuit with 1 resistance that changes according to user setting and battery output voltage.

That's what I was referring to.

Tapatyped
Yup. And I was trying to say the resistance in the upstream or battery circuit is not directly connected to the downstream or coil circuit, and therefore neither is relevant to the other.
 
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crxess

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Sadly, this is probably the tenth(at least) thread with these same discussions that I have read, that pretty much leaves every non electrical engineer going :blink:
There are literally millions of things people can devote their lives to that do not require a Degree in electronics.......................and they never get it.

Yet, as the thread progresses, it becomes more and more a - let my prove my knowledge -argument, and so confusing to some that they bail out, Understanding Less than when they started reading.:cool:

My question for the Experts - not clearly addressed in the opening post.

Rather than Watts Law vs. Ohms Law

Why precisely is Watts Law so important to the Average Vaper?

okay, Fight! :D
 
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fenderstrat

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Im not good at the qoutes thing yet,I will figure it out but I am at work right now(auto repair shop....lol and Im also a luthier)
but "batteries cant say no"
actually they can,its called venting and pretty much what all this is trying to avoid:evil:
"who cares about all the mathmatics and formulas?"
the guy that puts an 18650 designed for flashlights rated at 4 amps into a 75 watt evic mini...see above statement about venting:)
as Ive said before its not the quadratic equation or quantum physics its a 5th grade division problem...... watts divided by volts equals amps..........and it goes a long way to keeping you from burning yourself
 
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Dlmdavid

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If you're using a regulated mod, and your batteries are rated in Watts, then ...................

but...., the batteries are rated in amps.
Exactly, that's why you need to use watts law to determine your amps. Your batteries are supplying a set wattage, and the current is what flows through them to supply that wattage, the board itself does the adjustments to ensure you get that power to your coil, you only need to worry that your batteries can safely deliver your set wattage to the board, and in order to know that you use watts law to determine the current draw, because as you said, batteries are rated in amps
 

crxess

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Getting old. Gotten forgetful.

No shame in using aids:
Voltage to Wattage Chart

At one point in my life, Math was my love. I even maintained an inventory(very well) of over 15K parts and kept up with things in my head. Just one small part of my business. Those days are long gone due to life Stresses and health Issues.

Still, I manage to keep safe.;)
 

Douggro

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..but "batteries cant say no"
Actually they can, its called venting and pretty much what all this is trying to avoid:evil:
I did think about putting that in my original reply, but really, the battery is still trying to do what is being asked.
It just dies in the process. Spectacularly and dramatically. :D
 

sonicbomb

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Who cares about all the mathematics and formulas...
(IQ<50 && I<0.1)=Clouds

Because if you don't at least do the checks, the following formula may come into effect:
overstressed battery x pain and burns = big medical bills + scars

Sadly, this is probably the tenth(at least) thread with these same discussions that I have read, that pretty much leaves every non electrical engineer going :blink:
That was my point about muddying the waters. It's a good thing there is steam-engine because that makes it easy and requires no maths, which is nice. Having said that, watts divided by volts isn't exactly rocket science is it?
Oh, and to remember
D5enk9L.jpg
 
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Lessifer

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Just want to see if I understand.

On a variable wattage mod, to calculate the amp load from the battery(at a basic level):
Watts / battery voltage / number of batteries (not accounting for board inefficiency)

So if you have a 50 watt mod that uses a single 18650
at full charge it's 50/4.2/1 = 11.9 amp
at low voltage(more important) it's 50/3.2/1 = 15.6 amp

Is that right?
 

Topwater Elvis

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Using a regulated power device as battery voltage decreases, amp drain/demand from the battery increases.
50w / 4.2v = 11.90a (1 battery)
50w / 3.2v = 15.62a ( 1 battery )
Neither take device inefficiency into account.

Some folks sure try hard to make schtuf seem more complicated than it is.
 

AndriaD

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OP started this thread accusing people preaching secondhand misinformation, but has only muddied the water for you average vaper with no electrical engineering background.

Totally agree. I am almost entirely unable to do math, beyond simple arithmetic, so I depend on the Steam Engine calculator to figure all this stuff for me. But one thing I do know very well: the higher resistance the coil is, the longer the battery will last. So yeah, it's very important to know the coil's resistance -- without that piece of info, you can't even use the Steam Engine calculator to know what the amp draw will be. The higher the resistance, the lower the amp draw = longer battery life.

Andria
 
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