Dripping on mvp somewhat new

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Cg492310

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Nov 7, 2014
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Athens ohio
Okay. This is my first post after lingering a bit. Just got a mvp 2 and have multiple rdas. I love dripping and am content with them. I am checking out the math and whatnot for the perfect sweet spot for my builds. I typically vape .9-1.4 ohm single coil and want the best volts and power. I read that v^2/resistance=power but currently have a .9 ohm single coil 28 g and have it around 3.4-3.8 volts so in the formula says around 12 watts(3.3^2/.9=12). Is this what I should set it too? It just goes to 11. I just want to be able to tie all this info together so I can find my sweet spots myself using math. I like math. .9 ohm, 3.4 volts, and 8 watts is what I'm currently doing. Is this optimal? And any advice would be greatly appreciated to help me understand how these 3 factors(ohm,power,volts) tie in together to find optimal performance. Much love, caleb
 

gwhetzler

Senior Member
Verified Member
Jul 10, 2014
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San Antonio, TX
For the mvp... If you change the power aka watts then it will auto adjust the volts for you. If you adjust the volts then it will run the watts based off the math and your coil. You don't get to set both only one or the other.

As far what's optimal. .. well its what you like. Some times I run my stuff at .5 ohms and 15 watts or 25 watts or I run a .2 at 17watts. It all really depends on my juice and coil. I find what I like and remember to set it like that for that build and juice. Keep notes is my best advice. You might find a pattern.

Before I for get the mvp 2 will not fire a coil below .8 ohms and the ohm reader on it can be off by .2 ohms or more. Just an fyi
 
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The Ocelot

Psychopomp
ECF Veteran
Verified Member
Aug 12, 2012
26,497
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The Clock Barrens, Fillory
Hi and welcome!

1) The best power level is what tastes good to you. .← (period)

2) (Too much information alert)


Voltage is a measurement of input, it is the input coming from the battery into the system. Ohms is a measurement of resistance, it is what impedes the input. Watts are a measurement of output. It is the work product; the power produced, in this case heat that vaporizes the liquid. The interaction of the voltage and the resistance determines the amount of wattage produced. Amps are the current, the available energy, which in electronics is not like a flowing river. The current here is moved along by the volts.

Ohm's%20Law.jpg


The wattage isn't clearly illustrated in the picture, but it is how much of the amp guy is on the other side of the ohm from the volt guy.

The higher the ohms, that is the tighter the rope in the picture, the more volts would be required to produce the same amount of watts.

The interaction between volts and ohms is best illustrated with a fixed voltage battery device. For example:

I have a box mod that produces 3.7 volts. I can't change the volts, but I can change the devices that I put on it, which come in different resistances.

If I put a 2.2ohm atomizer on my 3.7 volt box mod it will produce 6.2 watts. But if I put a 1.5ohm atty on the same 3.7 volt device it will produce 9.1 watts, which is considerable warmer.

If you have a VV/VW device you have more flexibility since you can adjust the input, as well as the resistance, to change the output.



(For those of you who know better, I'm aware that I took a bit of creative license, but I'm trying to keep it simple and more practical than theoretical.)
 
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