First Mod - Confirmation or suggestions

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wrecks

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Jun 20, 2011
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I'm thinking of building a PV with this device I have laying around that I never use. It is intend to charge Cellphone/Iphones on the go. I use to used it alot when I traveled alot for work. I like the fact I don't have to start from scratch and it charges through a miniUSB. Also has a battery meter.

Here are the spec's of this box and some pictures.

Specifications:
Input (Mini USB) : 5VDC, 500mA Min.
Output (USB Type A Port) : 5VDC, 1000mA
Battery Chemistry: Li-ION
Battery Capacity: 4400mAh
Net Weight: 4.3 oz
Dimensions: 2.75" L x 2.10" W x .86" H

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I'm still reading through the guides that are stickied.

Here are my questions.
1. Just looking at the specs and pictures is it feasible to build my own PV?
2. Are the battery safe to use?
3. Quick and dirty mod, all I have to do is replace the on off button or add one and replace the USB connector to a 510 connector. I should be good to go?
4. It's rated at 5v output, can I mode it to do 5v and 3.7?
5. Does the 1000mA output affect performance? Is it to high or to low?

What would you folks do with this box? Does it have potential?

That is all I can think of now until some replies come in.
 
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korndogg

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Aug 19, 2009
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The batteries are very good batteries to use in a mod. The only problem I can see with it is the fact that it only outputs 1A. Everywhere I have read always say that an atty takes 2A to fire. I would still try it. Two 18650 batteries would last me about a week on a single charge! If it doesn't work, you have 2 awesome batteries to start with on a different mod. And yes, you can always plug a USB pt in the USB port and vape away! :vapor:
 

wrecks

Senior Member
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Jun 20, 2011
98
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Oahu
actually, from what i see of that board, a 5v 2a regulator in that position might just solve that problem.. I don't see any other circuits that should give you an issue.

Posted a picture from behind. You still think by changing the regulator, it may works? Also I don't get how it running at 5v output. The batteries are wired in parallel and I know each battery is rated at 3.7v each.

In addition what are the 2 capacitors for? It's labeled 'uf 6.3V 680(can't read the rest)
What is the copper cylindrical think in the middle?

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CraigHB

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Jul 31, 2010
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That unit uses a DC-DC inductance converter to increase output voltage above battery voltage. It boosts voltage by pulsing current through an inductor at high frequency, typically 100 to 500KHz. This type of DC-DC converter is used in many applications and is often referred to as a boost regulator or boost converter.

The big "copper thing" in the middle is the inductor, basically just a wire wrapped around a ferrous core sort of like a transformer. The large capacitors are a typical requirement for a boost regulator. They're used to smooth the pulsed voltage coming out of the inductor and make the output purely DC.

The part you're thinking is an output regulator is probably a MOSFET switch for the battery protection system, but I can't say for sure without seeing a schematic. The batteries used in that device are most likely LiCo based Li-Ion cells which require protection. The batteries must be disconnected by the circuitry when a fault is sensed.

Without a complete circuit schematic, it's going to be unlikely that you'd be able to figure out what to modify to increase current output, if it's even possible.
 
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