How come diff. coils with the same ohms heat up differently when volts constant?.

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flexsr

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Hey let's say 3 coils all have the same resistances and all use the same battery why would the amount of heat generated be different ? I tried a .5 fused Clapton coil, a single, and a dual on my mech and it. BArely would heat up. But a .5 ohm single would glow red hot.


The Power of all 3 coils is the same right? (same ohms and same volts).
P = (V^2)/R . Volts are constant and the resistance is same amongst coils so they all have the same Power ? How could that be? The 3 heat up drastically different.
 
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dustinmj

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Dual coils cut resistance in half.
You have to account for voltage drop on the battery.
Ohm's Law: V=IR... Need to account for battery limits and amps (I) before plugging into Watt's law.
Assuming you did all that, think about the dual coil situation...

P=(V^2)/R for a single coil where P=(V^2)/2R for a dual coil situation... half the power per coil, thus half the heat.
 

Bunnykiller

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each coil added reduces the "power" to the coils by the inverse of the number of coils...

1 coil = full power thru coil, 2 coils = 1/2 of the power thru each coil, 3 coils = 1/3 the power thru each coil... etc

or put this way... water flows into a bucket with 1 tube and drains at 1 gallon per minute
if the bucket has 2 tubes, then 1/2 gallon flows thru each tube in 1 minute... etc
 

flexsr

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Dual coils cut resistance in half.
You have to account for voltage drop on the battery.
Ohm's Law: V=IR... Need to account for battery limits and amps (I) before plugging into Watt's law.
Assuming you did all that, think about the dual coil situation...

P=(V^2)/R for a single coil where P=(V^2)/2R for a dual coil situation... half the power per coil, thus half the heat.

Oh. Gotcha ya now. I was actually thinking that exact same thing you mentioned when I was up all night tossing n turning and thinking of vape stuff. You explained if perfect. I get it now. .ugggh can't believe how dumb I was/am


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