Can we just use the normal conversion formula and divide thewattage by 2?
http://www.ohmslawcalculator.com/ohms_law_calculator.php
Always wondered why juice in low-ohm DCTs vaped so well atvoltages if figured with the standard formula should be way to hot. Imusing a Version 2 ProVari and a new LT that I believe also has the 3.5 high-ampsafety cut-off improvement with SmokTeck 1.5 ohm DCTs. Guessing because these have two 3-ohm coilswired in parallel giving a total resistance of 1.5 ohms at the connection pointto the battery, then in actuality its two coils, each firing at half the totalwattage of the circuit. So, if likevaping at about 6.2 watts with a 1.5ohm dual-coil carto I would need to set the voltageto 4.3 volts. Total amp draw (current)at connection to the battery is just shy of 2.9 amps and total wattage is slightlyover 12.3 watts, but in actually its two coils each firing at about 6.16 watts(my sweet spot). Is this correct?
http://www.ohmslawcalculator.com/ohms_law_calculator.php
Always wondered why juice in low-ohm DCTs vaped so well atvoltages if figured with the standard formula should be way to hot. Imusing a Version 2 ProVari and a new LT that I believe also has the 3.5 high-ampsafety cut-off improvement with SmokTeck 1.5 ohm DCTs. Guessing because these have two 3-ohm coilswired in parallel giving a total resistance of 1.5 ohms at the connection pointto the battery, then in actuality its two coils, each firing at half the totalwattage of the circuit. So, if likevaping at about 6.2 watts with a 1.5ohm dual-coil carto I would need to set the voltageto 4.3 volts. Total amp draw (current)at connection to the battery is just shy of 2.9 amps and total wattage is slightlyover 12.3 watts, but in actually its two coils each firing at about 6.16 watts(my sweet spot). Is this correct?