how do you 2x3.7V to 5V

[warp1900]

I'm sorry
i don't see the point in making that thing?
What advantage does that have over a kensington power pack?

I really don't get it

quovadis...

1- That "thing" costs a few dollars to make.

2- It doesn't need any attached wires that might get caught and torn or are just annoying.

3- If it breaks, it is easy (cheap) to replace or fix.

4- kensington and ANY mod are 2 different animals.

But the most important one is the satisfaction of making anything by yourself.

In the end, I understand by the way you ask your question that you believe that your kensington is the "hip" thing to use, and that this, or any other mod is for lower forms of life. Now you can go dial your iPhone and type your next post on your mac while you drink your mocha latte.

so... Quo vadis next?



^^^^

 

[mnealtx]

I'm sorry
i don't see the point in making that thing?
What advantage does that have over a kensington power pack?

I really don't get it

You can drop this in a shirt pocket and you don't have a long, dangling wire. As Stormy said - different strokes for different folks.

 

[zuel]

Can you tell me where your getting the boost regulator? Perhaps what model #?

I will be doing a 5V mod soon. It will consist of a single 3.7V cell and a regulated boost converter.

The atomizer will get a constant 5V all the way from full charge down to a dead cell.

 

[candre23]

Some people have been using this. It's a bit pricey, but it works well. Just be sure to use the caps specified in the data sheet for proper operation.

Madvapes is reportedly working on a custom-made cheaper alternative as well. No ETA yet, but it might be worth keeping an eye out for it.

 

[PriestSLC]

quovadis...

1- That "thing" costs a few dollars to make.

2- It doesn't need any attached wires that might get caught and torn or are just annoying.

3- If it breaks, it is easy (cheap) to replace or fix.

4- kensington and ANY mod are 2 different animals.

But the most important one is the satisfaction of making anything by yourself.

In the end, I understand by the way you ask your question that you believe that your kensington is the "hip" thing to use, and that this, or any other mod is for lower forms of life. Now you can go dial your iPhone and type your next post on your mac while you drink your mocha latte.

so... Quo vadis next?



^^^^

Wow, I use a iPhone and a iMac and I happen to be drinking a starbucks coffee and working on a regulated circuit for a 6 to 12 v input supplying a 5v 3 amp output...

I'll be sharing once it works of course...

No soup for you!


Sent from my iPhone using Tapatalk

 

[zuel]

Well I have made my first MOD that is still in prototype on a breadboard. I used two 10440 3.7v in series with a 7085 5v reg. Let me tell you. In comparison to my USB 5v passthrough, the vapor from the two batteries is very warm. I could not take a full drag because my atomizer was a bit trashed due to me cannibalizing it for the test.

I suspect that the two bats generates more watts for the atomizer and so my question of course now is,

Can you really get similar wattage off a booster?

 

[WillyB]

Well I have made my first MOD that is still in prototype on a breadboard. I used two 10440 3.7v in series with a 7085 5v reg. Let me tell you. In comparison to my USB 5v passthrough, the vapor from the two batteries is very warm. I could not take a full drag because my atomizer was a bit trashed due to me cannibalizing it for the test.

I suspect that the two bats generates more watts for the atomizer and so my question of course now is,

Can you really get similar wattage off a booster?

Folks tend to call anything with a USB cable a '5V PT', with a Joye atty they seldom are. You'll need 5V @ 2.4A to get true 5V vaping with a Joye 510. Your MOD is probably close, but note that 1A 7805 and those 10440 batts aren't up to task for long.

 

[zuel]

Folks tend to call anything with a USB cable a '5V PT', with a Joye atty they seldom are. You'll need 5V @ 2.4A to get true 5V vaping with a Joye 510. Your MOD is probably close, but note that 1A 7805 and those 10440 batts aren't up to task for long.

Expand your POV. What makes the 7805 and 10440 batts not "up to the task for long"?

 

[h8isgr8]

Can you tell me where your getting the boost regulator? Perhaps what model #?

Sorry for the late reply; you can get them through Texas Instruments sample program....... or buy it.

Plug-in Power Modules - Non-Isolated POL - PTN04050C - TI.com

If you are using two batteries in series, then a buck regulator can be used......

Plug-in Power Modules - Non-Isolated POL - PTH08080W - TI.com

 

[Ralph T]

Expand your POV. What makes the 7805 and 10440 batts not "up to the task for long"?

I think WillyB is talking about both items being underrated for the task. The 10440 doesn't have the capacity to provide 2.4 amperes of current... for long, if at all. By the same token, the 7805 is rated for 1 amp, not 2.4. Now, this 1A is for continuous use. Has to do with how much heat it can dissipate. In practice, we don't work them continuously, so that in and of itself probably wont be a problem.

But, the batteries will be severely over tasked. Because of this they wont last long between charges and it will reduce their lifespan. You would have a much better experience with the 14500 or even bigger batts.

 

[zuel]

But, the batteries will be severely over tasked. Because of this they wont last long between charges and it will reduce their lifespan. You would have a much better experience with the 14500 or even bigger batts.

I would expect the batteries to last similarly to the regular 510 batter, perhaps even longer. I am not looking for a vape all day long battery. But a simple 5v replacement for the 510 manual battery.

Are my expectations wrong for the batteries I have purchased?

I have already learned that the 7805 is not the regulator I am looking for. I need one with a control pin to avoid burnout on my tact switch.

 

[zuel]

Okay, trying to understand what would be the approximate run time of two 10440 350mah bats in series @ 5v 2.4a.

using this site: Battery Time Calc

I suspect that running the batteries in series means that mah is not multiplied by the number of batteries and therefore remains at 350mah.

The site above gives me a runtime of 8.75 minutes.

In comparison to the standard default Joye 510 battery at 180 mah. Making the assumption from other posts I have found, the default joye configuration runs at approximately 1.67 amps.

again using the site above the result is a runtime of 6.47 minutes.

This buys me 2.28 more minutes.

Assuming each drag is 6 seconds in length, every minute calculation above is 10 drags on the e-cig.

that means the standard 510 battery gives approximately 64.7 drags

while the 2x10440 in series gives 87.5 drags.

Taking a drag every 3.5 minutes then means 17 drags per hour

Giving Joy a 3.8 hour usage time

Giving the 2x10440 a 5.15 hour usage time.


The joy calculation is consistent with my usage miles so far so I can only expect to find I get 2 more hours with 2x10440 @ 5v 2.4 amps

sounds like a winner to me, so what do I have wrong?

 

[h8isgr8]

Zuel, how much space do you have to work with in your mod?

Perhaps if I can find some spare time, I could throw you together a circuit with a PTH08080W controlled by a FET switch. I'm sure I have the parts laying around here somewhere.

 

[zuel]

Zuel, how much space do you have to work with in your mod?

Perhaps if I can find some spare time, I could throw you together a circuit with a PTH08080W controlled by a FET switch. I'm sure I have the parts laying around here somewhere.

Thanks for the offer h8r

But I am just playing around trying to understand how this all works. Trying to getaway with a pen style mod as slim as possible, hence the 10440's.

Creating stuff is always such a rush. Just wish I knew the electrical side of this.

 

[WillyB]

Okay, trying to understand what would be the approximate run time of two 10440 350mah bats in series @ 5v 2.4a...

The joy calculation is consistent with my usage miles so far so I can only expect to find I get 2 more hours with 2x10440 @ 5v 2.4 amps

sounds like a winner to me, so what do I have wrong?

Your calculations seem fine and well thought out. You are satisfied with the runtimes, again fine.

But the one calculation you haven't done is the safe/max discharge rate of these 10440's. Are they meant to handle such a load safely? What's that figure and how will this affect the battery and the safety of the device while running them in series? Does it matter?

In general Li-ions are meant to be charged at 1C and discharged at 2C. Assuming the capacity of your batteries is accurate (it isn't, it's less) charging should not exceed 1C = 320mA, 2C discharging = 640mA. At the CPForums the AW rep said their high quality AW10440 battery has a max discharge rate of 600mA.

When we move up to a 14500 things improve. We'll use an AW14500 accurately labeled as 750mAh. The 2C discharge rate = 1500mA or 1.5A. The UltraFire 900mAh batts seem closer to 650mAh (1.3A). Seems to me this is where you want to be. Now do you see what I meant when I said the 10440's aren't up to the task especially with a Joye atty.

Looking at the AW14500's 1.5A discharge rate we see that even it is struggling in a one battery Joye 510 device which wants to pull 1.7A. It's workable though, I do it all the time and when the batts seem to die off rather prematurely I know why.

It's hard to find the various specs, but it seems many of the larger batts have a 2.5C discharge rate.

Some interesting reading on the joys of pushing your cells.

CandlePowerForums - View Single Post - Li-Ion protection technology and possible dangers

Someone on another post called the 10440's 'great' batteries... yea.

 

[zuel]

In general Li-ions are meant to be charged at 1C and discharged at 2C. Assuming the capacity of your batteries is accurate (it isn't, it's less) charging should not exceed 1C = 320mA, 2C discharging = 640mA. At the CPForums the AW rep said their high quality AW10440 battery has a max discharge rate of 600mA.

So with 2x10440 I am drawing ~2 amps more than the batteries are designed to do. Sounds dangerous. Good read.

I guess 3-5 mm more girth is probably a wise choice.

When my daughter was 6 she used to play this little game on the side walk. She would jump from panel to panel. When asked why she was jumping, she would say to avoid the hot lava. I think I will to jump too, but this time to avoid the molten lithium.

 

[5cardstud]

I use two 10440 with a 5 volt regulator in one of my mods. I use two 14500 with 5 volt regulator in one. I use two cr2s in one with 5 volt regulator and I have one with two 18650 with a 5 volt regulator. I don't have any problems with any of them and I use the UCC283TDKTTT-5G3 regulator in just about all of them.

 

[Connman]

So then with the regular stock 510 batteries they are of this type correct? being worked hard correct? with a very small mAh ratting so what makes them so safe according to the link you posted? Are they made up of only one cell and not two or something? Seems the 10440 would be a safer battery then factory stock batteries then unless they are one cell in the stock batteries which I haven`t taken apart yet but doubt they are..

And one more thing here the Batteries are protected and shouldn`t exceed the drain you are talking here or they should shut off. Am I wrong in thinking this?

Your calculations seem fine and well thought out. You are satisfied with the runtimes, again fine.

But the one calculation you haven't done is the safe/max discharge rate of these 10440's. Are they meant to handle such a load safely? What's that figure and how will this affect the battery and the safety of the device while running them in series? Does it matter?

In general Li-ions are meant to be charged at 1C and discharged at 2C. Assuming the capacity of your batteries is accurate (it isn't, it's less) charging should not exceed 1C = 320mA, 2C discharging = 640mA. At the CPForums the AW rep said their high quality AW10440 battery has a max discharge rate of 600mA.

When we move up to a 14500 things improve. We'll use an AW14500 accurately labeled as 750mAh. The 2C discharge rate = 1500mA or 1.5A. The UltraFire 900mAh batts seem closer to 650mAh (1.3A). Seems to me this is where you want to be. Now do you see what I meant when I said the 10440's aren't up to the task especially with a Joye atty.

Looking at the AW14500's 1.5A discharge rate we see that even it is struggling in a one battery Joye 510 device which wants to pull 1.7A. It's workable though, I do it all the time and when the batts seem to die off rather prematurely I know why.

It's hard to find the various specs, but it seems many of the larger batts have a 2.5C discharge rate.

Some interesting reading on the joys of pushing your cells.

CandlePowerForums - View Single Post - Li-Ion protection technology and possible dangers

Someone on another post called the 10440's 'great' batteries... yea.

 

[zuel]

So then with the regular stock 510 batteries they are of this type correct? being worked hard correct? with a very small mAh ratting so what makes them so safe according to the link you posted? Are they made up of only one cell and not two or something? Seems the 10440 would be a safer battery then factory stock batteries then unless they are one cell in the stock batteries which I haven`t taken apart yet but doubt they are..

And one more thing here the Batteries are protected and shouldn`t exceed the drain you are talking here or they should shut off. Am I wrong in thinking this?

good point. Is it possible we are at similar risks with the current 510 stock configuration?

 

[Rocketman]

The stock 510 battery has current limiting components designed into the circuit.
(other small overloaded semiconductors that will easily fail),
and
a blow out plug as big as the cell itself (the plastic lens cap).
I've had a 510 battery go thermal, and melt everything inside.
Lots of smoke, no explosion.
Lots of smoke.

Rocket