How does a mechanical mod work

[Stinkytofus]

For example,

i can use an ipv2 with nautilus and run it at 7 watts and get a good vape

my friends kayfun at 15 watts and get a good vape at .8 ohms

and my clt infinite at 25 watts

if i use an mechanical such as a cloned nemesis

if i use it with a nautilus how does it affect my tank, since i cant set wattage, how much power is used? Will i burn out my coils quicker?

as for the kayfun ?

And the clt infinite?

Pretty much my question is how does the mechanical mod apply its power for different tanks with different ohm setups, prebuilt or rebuilded, and since u cant set it to the wattage u want to use, how does that reflect on my three different tanks that i use on regulated devices

(where can i get a kick for a cloned nemesis and is the cloned nemesis by hcigar the best one or there is a better one)

thanks!

 

[prairie guy]

a fresh battery will produce 4.2v to the coil and and go lower as the battery is used. The coil ohms will determine on the output. And you can get a kick at alot of the ecf approved vendors online

 

[Johnnie Price]

A mechanical runs off of battery power only, so about 3.7 volts. Your wattage will be determined by the resistance of your coil unless you use a Kick or a Crown. 1.5 ohms at 3.7 volts is just slightly over 9 watts, which is what I vape on every day.

Make sure you also understand the amps limit of whatever battery you use. An ohms law calculator is your friend.

 

[tj99959]

In a nut shell your ipv2 is variable wattage, and a mechanical is variable resistance.

For example: I run my KayFun @ 9 watts with a 1.25 ohm coil. (VW)
Or, I use it with a 1.6 ohm coil on a mechanical.

With a mechanical we simply change the resistance to get what we want.

VV, VW, VR, they all do the same thing.

Ohms law as we use it is a circle, and there are always three ways to get where we want to go.

VW is like driving a car with an automatic transmission. It reads the resistance of the coil, and sets the voltage to give us the wattage we have it set at. VR is that car with a stick shift, we change the resistance to get the wattage we want.

 

[Ed_C]

One point that's not been brought up, is that a mechanical mod will start our at 4.2V and the drop off as you use it. So the wattage you're getting will drop off as well. With a regulated device the voltage or wattage will be held constant, therefore you won't have this drop off.

 

[Cullin Kin]

Ohms Law (V=IR) my friend, pure and simple. As others said, a battery will supply 4.2V fully charged and the rest depends on the coil resistance. Lets say you're using the 1.8Ω coils on your nautilus with a fully charged battery: V=4.2V I=Unknown (Amps) R=1.8Ω ---> Rearranging the equation we get I=V/R and plugging in we get I=4.2V/1.8Ω=2.33A being drawn from your battery. Now, if you want to know the power (wattage) we use a different equation P=V^2/R=I^2( R ) using these with that 1.8Ω coil we get P=(4.2V)^2/1.8Ω=9.8W. That's how mechanical mods work.

As Ed_C stated, your battery voltage will not remain constant throughout use so these numbers will change as your batteries drain as well as with voltage drop.

 

[bluecat]

As far as kicks go, I use the original kick from evolve and the smok kick in my nemy clones. Direct from evolve for the original. I got my smok kick from Madvapes.

 

[tj99959]

One point that's not been brought up, is that a mechanical mod will start our at 4.2V and the drop off as you use it. So the wattage you're getting will drop off as well. With a regulated device the voltage or wattage will be held constant, therefore you won't have this drop off.

That's true, but with a quality battery only the first couple of hits will be to hot, and only the last couple of hits to cold. For the majority of the battery charge the vape will be relatively the same.

 

[Stinkytofus]

Thanks guys ! That helps alot

 

[edyle]

For example,

i can use an ipv2 with nautilus and run it at 7 watts and get a good vape

my friends kayfun at 15 watts and get a good vape at .8 ohms

and my clt infinite at 25 watts

if i use an mechanical such as a cloned nemesis

if i use it with a nautilus how does it affect my tank, since i cant set wattage, how much power is used? Will i burn out my coils quicker?

as for the kayfun ?

And the clt infinite?

Pretty much my question is how does the mechanical mod apply its power for different tanks with different ohm setups, prebuilt or rebuilded, and since u cant set it to the wattage u want to use, how does that reflect on my three different tanks that i use on regulated devices

(where can i get a kick for a cloned nemesis and is the cloned nemesis by hcigar the best one or there is a better one)

thanks!

1: how much power is used:
That depends on the resistance of the coil;

2: will it burn out the coil quicker;
depends on what coil you put, I guess.

3: as for the kayfun; as for the clt infinite:
It's all up to you to know the numbers and work those things out for yourself.

4: how does the mechanical mod apply its power for different tanks?
A mechanical mod is just a container for the battery; you are just attaching the raw battery to the tank.

 

[roxynoodle]

Bear in mind, voltage drop as well in your calculations. I believe there's some as well in regulated mods, especially as power is increased.

My stingray has a 0.13 voltage drop when fired (based on other peoples' tests). So a fresh battery is applying 4.07v (4.2 - 0.13 = 4.07).

 

[edyle]

Bear in mind, voltage drop as well in your calculations. I believe there's some as well in regulated mods, especially as power is increased.

My stingray has a 0.13 voltage drop when fired (based on other peoples' tests). So a fresh battery is applying 4.07v (4.2 - 0.13 = 4.07).

No.
The amount that the voltage drops on your stingray depends on the resistance of the coil.
It is not some fixed value.
A lower resistance coil gives you a bigger voltage drop.


The real figure that characterises the mod as far as how much voltage drop you will get, is the resistance of the mod itself.