I thought 5v was 5v...?

Status
Not open for further replies.

CapeCAD

Senior Member
ECF Veteran
Verified Member
Jun 2, 2010
232
25
Massachusetts
Also any idea how long two 14500 batteries should last used in series?


I get 3 days of heavy vaping with (2) 14500 batteries in series. When batteries are fully charged I can only take about a 1 or 2 second draw before it gets hot, then it settles down and lasts a few days.
 

WillyB

Vaping Master
ECF Veteran
Oct 21, 2009
3,709
591
USA
So are the current ratings that over estimated. Even general ballpark (v/r=c) puts me under 2 amps with a three ohm atty. Or am I missing something...I would like my pass through to hit like my mod.

Cut down the PT's wires and hard wire this power supply.

NEW D-Link Power Supply AC ADAPTER 5V 2.5A JTA0302E-E - eBay (item 280344256363 end time Aug-03-10 19:09:49 PDT)

Or if you want to be absolutely sure this one (it should run cooler).

Genuine ITE SWITCHING AC ADAPTOR ADS6818-1505-WDB 5V 3A - eBay (item 290372974670 end time Aug-19-10 05:34:24 PDT)
 

Nuck

Ultra Member
ECF Veteran
Feb 14, 2009
2,265
10
Ontario, Canada
In series I`m getting a good day off mine. I vape 2 ml approximately a day. Take pretty near a 4 sec hit when I do vape as well. :2c:

Thats the problem with giving times as a rating as its completely subjective. 2x14500 in series has the same capactity as a single 14500 (real mah is about 750ish). If you use a simple regulator on it, all the excess power is wasted so its not a very efficient way to power your mod. Using a switching regulator is a much more efficient solution.
 

BuzzKill

Unregistered Supplier
ECF Veteran
Nov 6, 2009
7,412
5,145
65
Central Coast Ca.
www.notcigs.com
Thats the problem with giving times as a rating as its completely subjective. 2x14500 in series has the same capactity as a single 14500 (real mah is about 750ish). If you use a simple regulator on it, all the excess power is wasted so its not a very efficient way to power your mod. Using a switching regulator is a much more efficient solution.

Calculating efficiency can be very difficult between different regulation types , an LDO or analog regulator gets more efficient as the load across the regulator goes down ( I.E. less load is across the reg. and more is across the LOAD ) a boost circuit has better efficiency at higher voltages relative to the source voltage ( there are several other factors as well , capacitance , freq etc. )

An analog regulated setup uses the same amount of Power as a non regulated setup with the same load I.E. it will draw the same power , the only difference it that a regulator dumps the excess load across the regulator instead of the LOAD .

Boosted circuits work in a completely different way , they boost the voltage from a battery or source to a higher voltage , this requires the current to be lower to a degree OR the source needs to have a higher current capacity. They store the voltage and current in a capacitor in a pulsed PWM method ( Pulse Width Modulated ) it turns OFF and ON real fast. there are certain advantages to this design 1. it uses a lower voltage source ( like a single battery )

I hope this helps
Not all of the information provided here is guaranteed to be 100 % perfect but is a basic under standing of there designs and functions
 

48lowes

Senior Member
ECF Veteran
Verified Member
Nov 10, 2009
196
19
illinoize
Thats the problem with giving times as a rating as its completely subjective. 2x14500 in series has the same capactity as a single 14500 (real mah is about 750ish). If you use a simple regulator on it, all the excess power is wasted so its not a very efficient way to power your mod. Using a switching regulator is a much more efficient solution.

what switching regulator would you suggest?
thanks
 

48lowes

Senior Member
ECF Veteran
Verified Member
Nov 10, 2009
196
19
illinoize

If I'm understanding this correctly a regulator takes 2 series battries say 7.4v and takes it down to 5v, wasting power in the process. So with that understanding doesn't a switching regulator take series or parallel bats at 3.7v and increase the voltage to 5v?
And by the way it's good to see you posting here at the dreaded ECF. I know as a supplier you are limited and I thank you for your efforts.
 

Nuck

Ultra Member
ECF Veteran
Feb 14, 2009
2,265
10
Ontario, Canada
If I'm understanding this correctly a regulator takes 2 series battries say 7.4v and takes it down to 5v, wasting power in the process. So with that understanding doesn't a switching regulator take series or parallel bats at 3.7v and increase the voltage to 5v?
And by the way it's good to see you posting here at the dreaded ECF. I know as a supplier you are limited and I thank you for your efforts.

It takes the same 2 bats in series but uses PWM to do the same thing as a linear regulator without all the waste. That unit operates at over 90% eff. at the voltages and current we typically use for ecigs.
 

roadrash

Super Member
ECF Veteran
Apr 6, 2010
700
425
77
Hillsboro NH
It's meant for batteries in series. At 4.5v total, each bat is finished it's cycle.

Thanks for the info Nuck, I have a couple of those and after trying the 4050c booster with a 18650 bat and not getting enough power (1.63) to fire a lr510 attie, This was going to be my next step. I was hoping the 4050c would work and give me room for a juicer. I have to have a drip juicer, carts and cartos do not work for me. with the two bats in series, the mod will have to be bigger I guess. O well can't have it all.
Thanks again for sharing your knowledge.:D:D
 
Status
Not open for further replies.

Users who are viewing this thread