Introduction and a wiring question :)

Status
Not open for further replies.

brerbear

Full Member
Nov 18, 2012
24
8
Sweden
Hi Iam brerbear, a former 1-2 pack a day anlog smoker thats taken to vaping like fish to water since about a year back.
now iam running a Lavatube v1 with a 6 ml dct usually at 3.7 volt, but ive worked myself through anumber of
808s and egos aswell. I have been lurking here for a while mostly looking at reviews and in the modding forum.


oh and iam from sweden its friggin cold out now and you need to heat you juicecontainer in your hand when vaping because the cold makes the juice thicken enough to give aburned taste.

now for the wiring question i got some autoswithces from my old 808s and iam thinking about putting them into epipe mods kinda like the 601 but with a choice of 510 accessories. The question is is the cutout in the autoswitch and a 7 amp PTC-fuse enough protection if i were to use an unprotected Li-ion 18650 battery?
 

meli.

Ultra Member
ECF Veteran
Jul 10, 2012
1,030
938
Private Suite GroenDakkies
Hello and a Warm Welcome to ECF brerbear,
Can't say I envy the weather you're facing in Sweden, it's cold enough here in the UK. Brr
It never occurred to me cold weather would play such havoc with juice, gives a whole new meaning to freezing fog.:D

I can't help you with your switches hopefully you'll get some answers soon.;)
 

lazynothin

Full Member
Nov 25, 2011
7
0
US
My recommendation would be to go with a protected Li-ion such as the AW IMR. Don't risk it!

Might be worth a read through these two posts:
http://www.e-cigarette-forum.com/fo...9007-warning-rechargeable-batteries-apvs.html
http://www.e-cigarette-forum.com/forum/ecf-library/129569-rechargeable-batteries.html


7 amps may be too high. You might consider going down to 3 and possible 2.5. This all depends on the amperage you plan on pulling while generating heat (watts).
To calculate amps we take the voltage output divided by the resistance (ohm). Example: 4.8/2.5=1.92
To calculate watts we take the voltage output times itself and then divide by the resistance (ohm). Example: (4.8*4.8)/2.5=9.216
 
Status
Not open for further replies.

Users who are viewing this thread