I have always wondered what the loaded voltage reading is when vaping in HV battery. After seeing this video I think by now everyone has seen this, I wondered to myself is that was because of the density of the materials used somehow affected the voltage, there has been some discussion about this but no concrete evidence yet so I tried it myself.
I used this as my test set thanks to RalphT for coming up with this one.
2 freshly charged Tenergy 3.0v LiFePO4
510 atty resistance
Loaded Voltage
Amp check on the positive connection
Amp Check on the negative connection
This is the Battery Specs
New Chemistry LiFePO4 Li-Ion batteries:
Rechargeable LiFePO4 RCR123A 3.0V 750mAhBattery
Life cycle: 2000 times (Traditional Li-ion: 500 times)
Never explode or catch fire
Working Voltage:3.2V and Peak Voltage: 3.6V
Charging cut-off voltage: 3.6V
Discharge cut-off voltage: 2.2V
Please never overdischarge battery below 2.2V/cell
Charge the this battery with LiFePO4 RCR123A smart charger.
Capacity: 750 mAh
Maximum discharging rate:< 550 mA
Maximum charge current: <550 mA
Cell's dimension: 17mm Dia. x 34.5mm H.
Weight: 0.6 oz (18 grams).
After performing this experiment I had more questions than answers, are we really vaping 6v or 5v, I have no background in electronics and most of the people I asked about voltages always refer me to ohms law.
This a quote by one of the mods to explain Ohms Law
If you look at the data above the amps used when the battery is loaded is at 2.97amps the 510's resistance is at 2.1 using ohms law R(I)=E so that would mean that the working Voltage was @ 6.237v but then when batt loaded voltage was measured it was at 5.18V.
Secondly battery specs says Maximum discharging rate:< 550 mA so how come the reading is @ 2.97amps 8-o 8-o do I need a better multimeter
I used this as my test set thanks to RalphT for coming up with this one.
2 freshly charged Tenergy 3.0v LiFePO4

510 atty resistance

Loaded Voltage

Amp check on the positive connection

Amp Check on the negative connection

This is the Battery Specs
New Chemistry LiFePO4 Li-Ion batteries:
Rechargeable LiFePO4 RCR123A 3.0V 750mAhBattery
Life cycle: 2000 times (Traditional Li-ion: 500 times)
Never explode or catch fire
Working Voltage:3.2V and Peak Voltage: 3.6V
Charging cut-off voltage: 3.6V
Discharge cut-off voltage: 2.2V
Please never overdischarge battery below 2.2V/cell
Charge the this battery with LiFePO4 RCR123A smart charger.
Capacity: 750 mAh
Maximum discharging rate:< 550 mA
Maximum charge current: <550 mA
Cell's dimension: 17mm Dia. x 34.5mm H.
Weight: 0.6 oz (18 grams).
After performing this experiment I had more questions than answers, are we really vaping 6v or 5v, I have no background in electronics and most of the people I asked about voltages always refer me to ohms law.
This a quote by one of the mods to explain Ohms Law
The voltage and resistance will determine the current. It's ohms law. Like UberDuper said, the resistance of the atty and the voltage supplied will determine the current.
Example:
2.5 ohm is generally the resistance of 510 atty
Equation for determining current E / R = I
I=current
E=Voltage
R=Resistance
5 volt / 2.5 ohm = 2.0a
3.7 volt / 2.5 ohm = 1.5a
The current rating on a power supply is the most it's capable of producing, not how much it sends out. The amount of current is determined by the load (atty). If the voltage and resistance remains constant, it wouldn't matter if you hooked up a 10 amp power supply it will always draw the same amount of current.
If you look at the data above the amps used when the battery is loaded is at 2.97amps the 510's resistance is at 2.1 using ohms law R(I)=E so that would mean that the working Voltage was @ 6.237v but then when batt loaded voltage was measured it was at 5.18V.
Secondly battery specs says Maximum discharging rate:< 550 mA so how come the reading is @ 2.97amps 8-o 8-o do I need a better multimeter
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