mech mods

Status
Not open for further replies.

barneydale

Full Member
Jan 1, 2014
21
10
taylor mi
I have a mech mod and have always used it with no problem. Now i'm scared to use it because i hear that it can explode on you if the proper battery is not used, I was using an 18650 icr protected and was told that was dangerous and to only use an unprotected high drain IMR or a hybrid, si i got the Panasonic ncr18650 2900mah hybrid for my svd but i would think i should use a protected in a mech mod. any help please?
 

Revelene

Super Member
ECF Veteran
Sep 29, 2013
576
474
Kentucky, USA
You are correct in that using a protected li-ion battery is dangerous. In a mech mod, it is best to use either an IMR or hybrid IMR. Be sure to understand ohms law as well. You never want to push more current (amps) than the continuous amp limit on your battery. I believe that battery, the Panasonic NCR18650 2900mah, has a 10 amp limit.

Ohm's Law Calculator

Use this calculator to help. Use 4.2 volts as a starting point (as that is the nominal full charge of the battery) and put in the resistance (ohms) and press calculate. As long as the current stays under 10 amps, you will be fine as mechanical mods never perform the full 4.2 volts at a full charge due to voltage drop. Doing this keeps you in the safe zone.
 
It all depends on what ohm your wrapped at. If you're sub ohming then I wouldn't use an ICR. I use EH's 2100 mAh with a 60amp burst output and 30 amp continuous output. I'd much rather pay for the batteries than end up with a venting battery. Dangerous.

Sent from my Galaxy S5 using Tapatalk

1344432600_2_20_USD_7.00_dark.png
 

Baditude

ECF Guru
ECF Veteran
Apr 8, 2012
30,394
73,076
71
Ridgeway, Ohio
Last edited:

dice57

Vaping Master
ECF Veteran
Verified Member
Sep 1, 2013
4,960
3,734
68
Mount Vernon, Wa
yeah, loose the battery, you want an IMR high drain 30 amp continuous 18650 battery. The Sony VTC4 or 5 will do nicely. IMR are just a safer battery chemistry.

The reason the ICR's are protected, is that their chemistry is not the most stable, so it has a protection circuit the blows when it starts to be demanded of more than it can do before she blows. The unprotected are such that they don't require a protection because they are of a much safer chemisty, and won't blow up, they can vent if over taxed and misused, but no boom.
 

barneydale

Full Member
Jan 1, 2014
21
10
taylor mi
can someone help me? if i calculate 4.2 voltage (e) times resistance (r) 1.5 i hit calculate and the current(I) READ 2.8 and power read 11.76. now the battery is a Panasonic hybrid unprotected ncr 18650 2900mah 10amp. so is that a safe reading and if so why? does it mean i can set my power at 11.7 and voltage at 3.0 because i double the ohms to set the voltage. I'm really trying to understand this and i feel like I'm close so any help would be appreciated.
 

edyle

ECF Guru
ECF Veteran
Verified Member
Oct 23, 2013
14,199
7,195
Port-of-Spain, Trinidad & Tobago
can someone help me? if i calculate 4.2 voltage (e) times resistance (r) 1.5 i hit calculate and the current(I) READ 2.8 and power read 11.76. now the battery is a Panasonic hybrid unprotected ncr 18650 2900mah 10amp. so is that a safe reading and if so why? does it mean i can set my power at 11.7 and voltage at 3.0 because i double the ohms to set the voltage. I'm really trying to understand this and i feel like I'm close so any help would be appreciated.

I think you read something somewhere and confused yourself.

is that a safe reading
What? 2.8 amps? Yes; 2.8 amps on a battery rated for 10 amps is safe.
 

Revelene

Super Member
ECF Veteran
Sep 29, 2013
576
474
Kentucky, USA
can someone help me? if i calculate 4.2 voltage (e) times resistance (r) 1.5 i hit calculate and the current(I) READ 2.8 and power read 11.76. now the battery is a Panasonic hybrid unprotected ncr 18650 2900mah 10amp. so is that a safe reading and if so why? does it mean i can set my power at 11.7 and voltage at 3.0 because i double the ohms to set the voltage. I'm really trying to understand this and i feel like I'm close so any help would be appreciated.

(I) is your current in amps. At 2.8 amps you are well within the limit of your battery which is 10 amps.

The power means wattage output, voltage is the input, current is the speed or flow of electricity, and resistance is the impedance or interruption of flow.

Hope that helps!
 

dice57

Vaping Master
ECF Veteran
Verified Member
Sep 1, 2013
4,960
3,734
68
Mount Vernon, Wa
Welllll, the choke point is the 10 amps. That's just not much, no, not many amps at all. Not a lot of usable power, and can not be pushed very hard either. 30 amp continuous, 30 amp continuous, 35 amp and 50 amp continuous would be even better, but not 10 amp, just not enough usable power. You'll stop using them before they die, because once you use 30 amp batts, the 10 amp batts won't be used no more, cause they are pitiful. Waste of resources. lmao
 
Status
Not open for further replies.

Users who are viewing this thread