MG per ML question

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So in order to get 5mg of nic intake then one would have to vape the entire 1ml...correct.

If you are talking about the 5mg/ml resultant mix and not the 100mg/ml base. But then the situation is actually more complex than that. I could be way off here but this is my understanding:

It was originally thought that nic absorption was 10-40%, but then I heard close to 100% recently... kind of unsure about this part.

The pH of your nic solution changed the nic molecules from protonated to non-protonated as pH rises. In other words you get a more potent freebase nic experience. There are studies correlating more revenue from tobacco sales to the higher pH in products. Also, cigarette tobaccos tend to be more on the acidic side naturally and cigar tobaccos more base.
 

riverwinds

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OK. Let's say I have a 3 ml sampler bottle of 12 mg of nicotine. Would that be equal to 12 mg per ml. or 12 mg for the entire 3 ml bottle? I always wondered about that, as my exanalog had 1 mg per cigarette (1.5 packs per day smoker) and I only vaped 3 mls a day max. of 12 mg. Pros out there, please enlighten me!
 

Raenon

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OK lets take it that 1 ML is equal to 20 drops for this example. If you use 19 drops of no nic pg/vg and add one drop of 100mg/ml then the new 1 ML mix is now 5mg per ml. If that is the case then is there 5mg in each one of these drops in this mixture or is the total 1 ml mixture equal to 5mg.

Yes, if the drop was an even 1/20th of a ml (for arguments sake), and you're dealing with 100mg/ml liquid, you can divide the 100mg by 20, and each resulting drop of the 100mg liquid would have 5mg of nicotine in it. If that one drop is spread over an entire ml of liquid, you'd still only have 5mg of nicotine, in a ml. 5mg/ml

Please note that drops are a very imprecise measurement as they don't come out even, but if you're dealing with VERY small amounts, then you can use that. By the time you're counting 40 drops of something though, you should consider measuring in milliliters so that you're actually sure of what you're getting.

OK. Let's say I have a 3 ml sampler bottle of 12 mg of nicotine. Would that be equal to 12 mg per ml. or 12 mg for the entire 3 ml bottle? I always wondered about that, as my exanalog had 1 mg per cigarette (1.5 packs per day smoker) and I only vaped 3 mls a day max. of 12 mg. Pros out there, please enlighten me!

If it's "12mg" liquid, they mean "12mg/ml"
A 3ml bottle would be 3 x 12mg = 36mg in the entire bottle.
 

Raenon

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It occured to me after writing the last response that some people may actually benefit from a visual metaphor to help understand the way that a mix works, especially given the fact that most of us on this board didn't grow up working with metric measurements.

Imagine that each ml of liquid is a bucket filled with 1000 marbles. This is the same as the 1 gram (1000 mg) of total mass to each milliliter.
100mg would be 100 nicotine marbles in 900 VG/PG marbles (lets ignore flavor for now ;) )
Each bucket could be broken down into 20 scoops (drops)

If you took a scoop of these marbles, assuming they were very well mixed, you'd get 5 nicotine marbles, and 45 VG/PG marbles.

If you drop that scoop into a fresh bucket, and fill it up the rest of the way with 19 scoops of VG/PG marbles (950 more of them), you still end up with only 5 nicotine marbles, and now 995
total VG/PG marbles. If you evenly mixed it, each scoop of this new bucket will have less than 1 nicotine marble in each scoop (since mg isn't really a single object, you'd have to imagine partial marbles... that's where this metaphor would break down a bit).

If you had a premixed liquid, at the 12mg/ml mentioned earlier, that'd be 12 nicotine for every bucket. 3ml would be 3 buckets, so 36 total nicotine units.

I hope that you can also see my earlier point that getting even "scoops" would be very difficult, just the same as getting even drops.

Does that help anyone?
 

ncvaping

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Let me make sure I have this right. Using only the 19 drops and one drop of 100mg/ml nic. The resulting mix would be 5mg/ml. (based that each drop is equal for both ingredients) Then each drop of that mix would be a percentage of 5mg/ml not 5mg of nic per drop. To absorb 5mg of nic one would have to vape the entire one ml of this mix.
 

Raenon

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Let me make sure I have this right. Using only the 19 drops and one drop of 100mg/ml nic. The resulting mix would be 5mg/ml. (based that each drop is equal for both ingredients) Then each drop of that mix would be a percentage of 5mg/ml not 5mg of nic per drop. To absorb 5mg of nic one would have to vape the entire one ml of this mix.

That is correct.
 
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