Mixing Math

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TotesBananas

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Mar 2, 2018
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Hey All,

Sure this has been done at some point, trying to tinker with an ejuice (relative newb here) I made and wanted to change the flavor profile a bit. Basically had a 10ML bottle that had 9ML base nicotine solution (70/30), ie 90% and 1ML of flavor broken up into A,B, C, and D. These flavors were represented at 2%, 2%, 2%, and 4% respectively, (or .2ml, .2ml, .2ml, .4ml). I drew out 2ML of the overall solution and decided flavors C and D were too strong, while flavors A and B were too weak. If, I want to bring the solution back to 10ML while changing the percentages to around A:2.5%, B:2.5%, C:1.5%, and D:3% - what are the amounts of flavor needed for A and B within the 2ML I'm adding back to the original solution?

Aaaaand is there a formula that works here so I can figure this out on my own next time?

I'm guestimating I need about .06 or .07ml within the solution, but that's just with my eye balls and logic.
 

TotesBananas

New Member
Mar 2, 2018
3
1
40
Snick, appreciated but this seemed too complicated to figure out how to backwards plug this into the calculator.

AzP, those numbers seem to make sense, and I think I see how I can use this formula going forward, thank you. And you're saying basically that C and D will be at 1.6 and 3.2% naturally lowered by the new 2ML I'm putting in, correct?

Thanks again both of you!
 
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