Need help to grasp current (Amps)

[MMcQ]

Okay.. I wonder why they're selling a 200W Box with 2 batteries if you can possibly only get 90 Watts out of it..
Are they trying to kill people or what?

and that's where the REAL magic happens

 

[inspects]

Here is some good information about batteries, in case you haven't read it. List of Battery Tests | E-Cigarette Forum

 

[Vaping_Racoon]

LOL please explain, gosh I'm so lost with all this

 

[skoony]

Note that atomizer resistance does not play a part in this equation.

Again the resistance is an important part. It determines how the circuit operates.
With out knowing the resistance how would one know if the regulated mod would even
fire?
A regulated mods main feature is to be able to switch coils of different known resistances
to know if your device will operate within those parameters with out doing the math
before swapping. You determine before hand what resistances will work.
Mike

 

[Vaping_Racoon]

Here is some good information about batteries, in case you haven't read it. List of Battery Tests | E-Cigarette Forum

I did but I'm still lost as to how a regulated works..

 

[Vaping_Racoon]

Like why can't I use more than 90 Watts :S

 

[Vaping_Racoon]

I seen a youtuber crank up the full 200W of a device with only 2 18650's (20A)

 

[MMcQ]

From what I'm gathering the mod will fire whatever it says it will fire. So if its like " .1 ohm to 3 ohm" and you give it a .1 ohm coil its gonna try to fire it. Now if there's 2 30 amp batteries in there its gonna let you fire it up to 200 watts. But that'll pull (ideally) 31.5 amps. 200/6.4 at low voltage with no loss in there.. So you'd be exceeding the cdr of your batteries, but it's a pulse drain since you can't vape (or can you) for like 5 or 6 minutes till the batteries die. If there's only 2 20 amp batteries its gonna try to fire it, and possibly fail i.e. "low voltage" reading or so.. or it succeeds, yay pulse rating junk. And it lessens battery life or maybe vents, who knows. But the device will only pull 31.5 amps at max without regard to what you put in it. How it does it? I dunno.. magic to me

 

[Vaping_Racoon]

Some guy wrote this on a review of my mod (Kbox 200W) and I have 30Q's, should I not worry then?

Its totally dependent of batteries amperage. Take the 30Q's well documented to be stable at 40amp draw. 7.4v@40amp. 296w. I use the 30Q because they are popular. These are regulated mods, with an assortment of safety caps. One reason I'm an advocate of regulated modular builds.

 

[bwh79]

Again the resistance is an important part. It determines how the circuit operates.
With out knowing the resistance how would one know if the regulated mod would even
fire?

A regulated device will either fire a coil or it won't, but my point was, that in the context of figuring battery amp draw (which is the current topic of discussion, here), the resistance of said coil is not a determining factor.

 

[fenderstrat]

you can pull 200 watts out of 2 batts because we are PULSING them.Some batts that are 20 amp cdr and they may have a 30 or 35 or even 40 amp pulse capabilty.So for 5-10 seconds they can deliver what is needed
even at 200 watts a 2 battery series mod AT FULL CHARGE is pulling 23.8 amps so its not an outrageus demand.
I am just guessing here but I would think that as the battery drains the mods will not actually put out the full 200W.
The 200 watt thing is misleading anyway cause what coils are rated for that ??200W is just the vaping worlds way of saying "mine is bigger"

 

[Vaping_Racoon]

Yeah I don't plan to actually use 200W, I just wanted to understand better and make sure I wouldn't be doing anything stupid, giving a bad rep to the community.

Thanks alot guys, now I get it.

 

[beckdg]

low builds ARE very dangerous on a MECH mod as there is no control and a battery can be taxed till it vents.A reg mod simply wont fire
I dont know of any recent regulated mod that will let you do dmage to the batts.there are numerous protections in place.
Yes I'm sure someone could do it but under normal vaping conditions regulated mods are pretty safe. just remember Watts div by Volts = Amps you can multply by .9 if you want but you get the idea

Though electronics fail.

Better to spec your batteries CDR to your power setting than rely on a safety net that may not be there.

Tapatyped

 

[skoony]

A regulated device will either fire a coil or it won't, but my point was, that in the context of figuring battery amp draw (which is the current topic of discussion, here), the resistance of said coil is not a determining factor.

Resistance will be the determining factor when the circuit fails.
Mike

 

[chinacatsunflower-]

The following is a really good link that I believe will help clear up a few questions you're having, as well as teach you a couple things you might not have known but should. Such as how parallel and series both create the same benefit, but in a different way:

• Parallel increases your maximum capacity by combining their amps. Two 20 amp batteries would give you a 40 amp capacity, but you'd still have 3.7v.
• Series increases your maximum voltage by treating the cells as one. Two 20 amp 3.7v batteries would still give a 20 amp capacity but will boost your available voltage to 7.4v, which in turn reduces the amount of amps that need to be drawn.

It will also explain why resistance has nothing to do with the current being drawn for a regulated mod.
To find out the current being drawn for a reg mod, it is I=P/V (Amps = Wattage / Voltage).

Here it is:
PSA: You Don't Calculate Current Draw on Regulated Mods Like You Do on Mech Mods • /r/electronic_cigarette

 

[Vaping_Racoon]

Cool, I'll check it out

 

[Topwater Elvis]

---> Battery pulse ratings are useless! | E-Cigarette Forum

Using a regulated power device as battery voltage decreases amp demand from the batteries increase.
2 cell power device at low voltage cutoff.
200w / 6.4v = 31.25a

Samsung 30Q's are not "stable at 40a draw" ---> Samsung 30Q 20A 3000mAh 18650 Bench Retest Results...a great 20A/3000mAh battery!

 

[MMW]

Varping Racoon, on 2 18650s you can go over 90w.
Say the cut off voltage for your regulated series mod is 3.2v.

In a series take the cut off voltage x2batts.
6.4v × 20a= 128w. That is at the cutoff voltage where it will draw the most amps.

EDIT:
The above is based on 20a batts.

 

[IMFire3605]

Hi guys,

so I'm looking at my calculator and I'm wondering about how the current works.

Let's say I have a Dual Parallel 0.2 ohms build, the calculator says:

Based on 3.7[V] - Current 18.5 [A] - Power 68.5 [W]

So.. if I have 2 Batteries rated at 20 Amps, I should be safe if the current drawn is
18.5 [A] ?

What happens if a build goes over 20 [A] ?

lol, thanks for helping me understand.

On a Mech use "Ohm's Law" with the fresh charge figure, this will be the highest amps the build will pull and decreases as charge decreases.
4.2v/your ohms (resistance)=your max amps, 3.7v is the nominal voltage a Liion battery is rated at, but fresh off the charger the voltage is 4.2volts
Parallel Dual Battery box mech still use 4.2v, but your Mah and Amp load is split on the two batteries, so 2 identical Samsung 25R batteries, rated at 2500mah and 20amp CDR, 4.2volts output at fresh charge, but your Mah is equal at 5000mah and your CDR is 40amps

Regulated mod you use "Watts Law"
You wattage or mod's max wattage/lowest battery cutoff charge (most mods this is between 3.0 and 3.6v, average 3.2volts)=max amp pulled off the batteries.
Single battery 60watt mod, 60watts/3.0volts=20amps
Dual Battery Series 120watt mod, 120watts/6.0volts=20amps (in series voltage is doubled but mah and amp limit stays what a single battery handles)

 

[Romenov]

ahh ohm's law, come back with regulated box and sub-ohm tanks, it's much safer I think.