Question about batteries and voltage

[betterthanyou]

I am looking at the AW IMR 18650 2000mah battery. Under the description it says:
Nominal working voltage- 3.7V
Peak voltage- 4.2V

So a provari can be set anywhere from 3-6V. Using this battery in a provari, what happens when you set the voltage on the device to something above 4.2V? Do you need a battery with a higher peak voltage to run higher voltage settings?
And what does nominal working voltage mean?

 

[genoks]

i think it will just top off at 4.2 which is where the aw battery is set to produce at peak.

 

[OlDogNewTricks]

It will cut the current - Voltage = Current (I) * Resistance. Good luck and have fun!

 

[betterthanyou]

how do you run more than 4.2v on a provari?

 

[happydave]

how do you run more than 4.2v on a provari?

you just crank it up to 6.0 volts. the device has capacitors in it that can put out 6.0 volts.

a capacitor is like a holding tank for electricity. once the capacitor is full it can release a steady flow of electricity at a desired rate or it can release it all at once.

 

[OlDogNewTricks]

You run at lower current. The circuitry drops the current to produce higher voltage. The resistance is fixed by your atomizer, so the higher the voltage, the lower the current and vice versa. Good luck and have fun!

 

[Topwater Elvis]

how do you run more than 4.2v on a provari?

The Provari has circuitry that uses the battery's power to boost the output to the the level set.

 

[happydave]

You run at lower current. The circuitry drops the current to produce higher voltage. The resistance is fixed by your atomizer, so the higher the voltage, the lower the current and vice versa. Good luck and have fun!

Bro, By Ohm's Law, Current (I) is directly proportional to the Voltage (V) if Resistance (R) and Temperature remain same.
I = V/R.....or...R=V/I.....or......V=IR.

so if we are running
6.0 V and a 1.5 Ohm coil I= 4 amps
3.7 V and a 1.5 ohm coil I= 2.4 amps

The circuitry can not drop the current to raise voltage because, Current (I) is directly proportional to the Voltage (V).

 

[Plumes.91]

The coil gets hotter and vaporizes more juice up to 6 volts with an AW battery. AW batteries are the only batteries provape recommends. use of another battery voids the warranty. the provari boosts the battery voltage up to 6 volts as long as your using a higher resistance atty. recommended atty is around 2 to 3 ohms.

 

[Baditude]

The coil gets hotter and vaporizes more juice up to 6 volts with an AW battery. AW batteries are the only batteries provape recommends. use of another battery voids the warranty.. the provari boosts the battery voltage up to 6 volts as long as your using a higher resistance atty. recommended atty is around 2 to 3 ohms.

That's not totally correct. Provape does "recommend" using an AW IMR button top battery several times on their website, however you can use other IMR/hybrid batteries safely in the Provari and doing so will not void the warranty. Those must be button top.

Provape does forbid using magnets on flat top batteries, which WILL void the warranty. Restricting the Provari to using button top batteries is an intentional safety design feature to prevent a user from accidentally putting a battery in backwards, which can cause very bad things to happen (reverse polarity).

Regulated mods, and drop-in regulated circuit modules like the Kick, use buc boost circuitry to acheive higher voltages from a 3.7 volt battery. This uses technology using PWM (pulse width modulation). This requires a high drain battery, which an IMR battery is. That's the gist of it; if you need a more technical explaination read this from Provape - http://www.e-cigarette-forum.com/forum/provape/334831-technical-why-high-drain-batteries.html

 

[OlDogNewTricks]

Bro, By Ohm's Law, Current (I) is directly proportional to the Voltage (V) if Resistance (R) and Temperature remain same.
I = V/R.....or...R=V/I.....or......V=IR.

so if we are running
6.0 V and a 1.5 Ohm coil I= 4 amps
3.7 V and a 1.5 ohm coil I= 2.4 amps

The circuitry can not drop the current to raise voltage because, Current (I) is directly proportional to the Voltage (V).

Whew, that'll teach me to think when I haven't slept. I apologize. You are correct.

 

[betterthanyou]

Bro, By Ohm's Law, Current (I) is directly proportional to the Voltage (V) if Resistance (R) and Temperature remain same.
I = V/R.....or...R=V/I.....or......V=IR.

so if we are running
6.0 V and a 1.5 Ohm coil I= 4 amps
3.7 V and a 1.5 ohm coil I= 2.4 amps

The circuitry can not drop the current to raise voltage because, Current (I) is directly proportional to the Voltage (V).

Was he incorrect in that dropping the current proportionally drops the voltage? v=ir?

 

[OlDogNewTricks]

Yes, I was and apologize. Wasn't setting out to mislead you. It is the circuitry that pumps up the voltage, but please make sure that you are using the manufacturer's recommended battery if you are running over 3.7 volts.