Question about low resistance 510 atty's

Status
Not open for further replies.

Papa Lazarou

Ultra Member
ECF Veteran
Nov 15, 2008
1,429
231
UK
Yes there is a difference. To use a simple analogy, you can think of it like a light bulb. A 60 watt bulb represents a standard atty, and a 100 watt bulb represents a low resistance atty. A 100w bulb does have a lower resistance than a 60w one - its exactly the same principal. You can replace a 60 watt bulb with a 100 watt in the same socket (providing the fitting is rated for it) and you'll get more light, but obviously it uses more electricity.

So low resistance atty's draw more current from the battery, so with everything else being equal, the battery life will be shortened. The benefit is that they run hotter, and therefore produce a thicker, denser vapour and more of it. Some people find that they take shorter drags with the LR atty's so it can turn out that the battery life is not shortened by that much in practice.

Personally I use both. I find some the flavour of some juices don't stand up to the extra heat from LR, and prefer them on a standard atty. Others do benefit from the extra heat. LR atty's give a stronger throat hit, use more liquid and usually need to be direct dripped as cartridges tend to be unable to feed liquid to them quick enough. Another point to be aware of is LR atty's don't last as long, and usually only have a DOA warranty (they can last for quite a while if you're careful but it's the luck of the draw I find, some burn out within a week or two).

Hope this helps!
 
Last edited:

Hoosier

Vaping Master
ECF Veteran
Jan 26, 2010
8,272
7,903
Indiana
To add to the good illustration above:

As I'm sure you've guessed, the difference is resistance. A lower resistance atomizer consumes more current, reducing battery charge time, and produces a warmer vapor.

Why? V=IR. Voltage = Current * Resistance. Since our voltage is fixed a little algebra might help. I=V/R. Current, in amps = Voltage / Resistance, in Ohms. If you have a 650 mAh battery you have 0.650 Amp-hours of charge. ("m" is for milli). So a fairly typical 2.5 Ohm standard atomizer being fed by a typical 3.2 volt (loaded voltage) eGo battery is I=3.2/2.5 = 1.28 amps so your battery could fire that atomizer for about half an hour in a perfect world. If we plug in a LR 510 atomizer at 1.5 Ohms we get 3.2/1.5=2.13 amps so your 650 would be able to fire the LR for less than 20 minutes in a perfect world. (Since we only fire them a few seconds at a time or they would burnout, and battery performance degrades with charge level, these calculations are only good to give comparison numbers.)

So, we now know the LR's reduce battery charge time, but since more current is being consumed there is more heat. Heat is also power and can be expressed as Watts. Watts are the product of potential and flow. W=VI. Watts = Volts * Amps. We can substitute our previous I=V/R into that for W=VV/R. Watts equals voltage squared divided by resistance. Plugging the same numbers into that for the standard atomizer W=3.2*3.2/2.5=4.1 Watts. For the LR atomizer 3.2*3.2/1.5=6.8 Watts. A jump of more than 50% in power, aka: heat, so it should be something you can feel.

Or to simplify, Standard 510 atty = longer battery time & cooler vapor while a LR 510 shortens battery time & hotter vapor.
 
Status
Not open for further replies.

Users who are viewing this thread