Regulated mod
Atomiser side - For a given wattage, a higher resistance coil will need more volts, a lower resistance coil will need more amps. The regulator chip will take care of this balance for you, it may also display this data though it is of absolutely no use to the user. This has no influence what is happening electrically on the battery side of the regulator.
60 watts at 3.0 Ω = 13.42 volts and 4.47 amps
60 watts at 2.0 Ω = 10.95 volts and 5.48 amps
60 watts at 1.0 Ω = 7.75 volts and 7.75 amps <---
60 watts at 0.5 Ω = 5.48 volts and 10.95 amps
60 watts at 0.25 Ω = 3.87 volts and 15.49 amps
60 watts at 0.1 Ω = 2.45 volts and 24.49 amps
The balance of volts and amps is equal at 1 ohms, increasing with a linear ratio above that. Below 1 ohm the ratio of amps to volts increases exponentially. I'm not an electrical engineer or a physicist or a chip designer, so I cannot explain why this is.
This is why regulators have pre-programmed coil resistance range limitations.
Battery side - The regulator chip will increase the amount of amps it draws as the voltage in the battery decreases to maintain the selected wattage. The regulator can measure the remaining voltage in the battery. It uses this information to calculate how many amps to draw to provide the selected wattage, what value to show on the battery meter, when to cutoff operation, and depending on the mod it will reduce the wattage to allow for detected battery voltage sag.
The regulator does not know the amp limits of the battery. However if it reacts to voltage sag then this may serve as a form of protection from drawing to much current from the battery, though you would be a fool to rely on this.
Atomiser side - For a given wattage, a higher resistance coil will need more volts, a lower resistance coil will need more amps. The regulator chip will take care of this balance for you, it may also display this data though it is of absolutely no use to the user. This has no influence what is happening electrically on the battery side of the regulator.
60 watts at 3.0 Ω = 13.42 volts and 4.47 amps
60 watts at 2.0 Ω = 10.95 volts and 5.48 amps
60 watts at 1.0 Ω = 7.75 volts and 7.75 amps <---
60 watts at 0.5 Ω = 5.48 volts and 10.95 amps
60 watts at 0.25 Ω = 3.87 volts and 15.49 amps
60 watts at 0.1 Ω = 2.45 volts and 24.49 amps
The balance of volts and amps is equal at 1 ohms, increasing with a linear ratio above that. Below 1 ohm the ratio of amps to volts increases exponentially. I'm not an electrical engineer or a physicist or a chip designer, so I cannot explain why this is.
This is why regulators have pre-programmed coil resistance range limitations.
Battery side - The regulator chip will increase the amount of amps it draws as the voltage in the battery decreases to maintain the selected wattage. The regulator can measure the remaining voltage in the battery. It uses this information to calculate how many amps to draw to provide the selected wattage, what value to show on the battery meter, when to cutoff operation, and depending on the mod it will reduce the wattage to allow for detected battery voltage sag.
The regulator does not know the amp limits of the battery. However if it reacts to voltage sag then this may serve as a form of protection from drawing to much current from the battery, though you would be a fool to rely on this.