Single vs Dual Coil - Same Voltage

[Violetti Usva]

One of the posts on my Reload (clone) broke so I took out the coil and blocked out the excess surface area. I expected it to be hotter - I'm running it on a mech mod so the same voltage would be running through half the wire mass and I thought that higher resistance means more energy is lost as heat. To my surprise it's slightly cooler than before - where is my understanding wrong?

My thoughts are:
1) My attempt to block the excess surface area with a bit of cotton threaded through each airflow hole for the other coil isn't working very effectively and the vapour has more room to spread out and cool down in the chamber;
2) The amperage controls heat instead of resistance and I was previously mistaken?
3) You tell me

 

[bombastinator]

I’m not sure I follow this whole blocking out thing. In general though I would guess that halving the amount of metal you are heating may have something to do with it.

 

[Violetti Usva]

I just put extra cotton in the space where a coil was to attempt to keep the density of vapour in the chamber consistent with that of the dual coil, albeit unsuccessfully.

 

[Steve Parry]

No, on a mech mod the lower the resistance the more heat is created. The higher the resistance, the cooler the vape.

 

[rjeatkrconley]

One of the posts on my Reload (clone) broke so I took out the coil and blocked out the excess surface area. I expected it to be hotter - I'm running it on a mech mod so the same voltage would be running through half the wire mass and I thought that higher resistance means more energy is lost as heat. To my surprise it's slightly cooler than before - where is my understanding wrong?

My thoughts are:

2) The amperage controls heat instead of resistance and I was previously mistaken?

Correct. The same voltage supplied at different amperages produces different results.
In a mech mod, this is controlled by the resistance.
In a regulated mod, it's controlled by the board.


Sent from my Z982 using Tapatalk

 

[Flavored]

One of the posts on my Reload (clone) broke so I took out the coil and blocked out the excess surface area. I expected it to be hotter - I'm running it on a mech mod so the same voltage would be running through half the wire mass and I thought that higher resistance means more energy is lost as heat. To my surprise it's slightly cooler than before - where is my understanding wrong?

My thoughts are:
1) My attempt to block the excess surface area with a bit of cotton threaded through each airflow hole for the other coil isn't working very effectively and the vapour has more room to spread out and cool down in the chamber;
2) The amperage controls heat instead of resistance and I was previously mistaken?
3) You tell me

Watts (heat) = Volts X Amps . . . when you removed 1 coil, amps went down by 1/2, so 2 is kinda correct.