With your specs... I get 126.4mm wire length for a net resistance of 0.25Ω / 101mm for a net resistance of 0.20Ω... and 50.6mm for 0.1Ω net.
Twgbonehead may have something here, but would require a decent bit of research to validate or shoot down.
Kanthal A1 is comprised of iron, chromium and aluminum. When heated, an aluminum oxide layer, both thermally conductive and electrically resistive, is promoted to the wire surface. As long as a sufficient alumina (Al₂O₃) layer exists, surface electrical conductivity remains minimal.
Possible questions are...
What is the most likely, electrically resistive oxide layer produced by 317L, and at what temperature is it promoted to the surface... if any?
What determines the conversion from metal to metallic oxides... if it's temperature, does temperature alone promote oxides to the surface, or does the specific metallurgy play a roll?
The melting point of aluminum, at 1,221°F, is well within the functional parameters of Kanthal A1, which has a melt point of 2,732°F... while the basic melting points of the most likely oxide promoting metallic compounds found in 317L are:
nickel - 2,650°F
chromium - 3,465°F
molybdenum - 4,753°F.
Interesting that the melting point of 317L is 2585+/-°F... well below the melt point of the above 317L individual metal components. Ignoring the specific temperatures for a moment, and taking into account other temperature "controls" like oxygen, lets run with a stand alone question...
Of the above metals, which is the most likely (if any) to provide a "Kanthal A1 like" high thermal conductance with low electrical conductivity, under the conditions found in an vaporizer/atomizer... and of those which is the most likely to occur?
As I have time - although I may be barking up the wrong tree - I'll research these questions. If anyone else would like to conduct a bit of research themselves... don't let me hold you back. ;-)