Wow, thanks for all the replies, that was generous of you, again.
--> 5K (502) for me, not 50K
Oops, yea 5k, not 50k.
This chip does not limit the power output, Input current limiting with R6 on my schematic . this resistance only serves to protect the transistor. R6=0.020 --> Imaxinput=7A -->See the datasheet for more informations
I only did a quick look at the data sheet. I see that now. That's good then.
Yes input, of course. 20-25w seems to be the max for me (Pspice simulation).
Well, simulations are simulations. I'd check that on the bench.
The most important, What's your frequency ? For me 750Khz, --> reducing the size of capacitors.
550kHz with 200u, 680kHz with 100u. Problem is that efficiency drops as frequency goes up. Don't want to run it any higher than I need to. My simulations tell me I can run lower value output caps, but simulations don't account for all factors. I usually get around double the output ripple when measured on the scope compared to the simulation. But hey, if it works, then great. My concern is destabilizing the controller with excessive ripple and also the noise it generates.
No at this moment, Power transfer between L2 and C7,C8,C9 . to put them close to each other.
True there is an amount of power transfer going on
through the caps and atomizer, but all of the input ripple and converter startup transients return
through the ground plane to battery negative. That's a considerable amount of cross inductance for any traces above it. I would not run a shared plane, but if you say you have no issue, then great.
3v MCP1700 regulator on my board and 5v from USB connector.
I don't see that regulator in the schematic, where is that thing? Am I blind or something?
I don't understand the purpose of D1. If it's connected to USB power, then it's not a clamp to protect against a USB over-voltage condition. What does it do?
I use internal ADCreference = 1,024v. For current sensing : Rshunt = 0,1 Ohm , Vref=1,024v, Conv = 1024 --> 10mA
Yes, I see the newer PICs have that feature. I haven't used any of the most recent ones. The PIC24Fs I've been I'm using and the PIC18Fs I've used before that do not have an internal voltage reference. Even so, I mistakenly assumed the current
sense resistor was 10mΩ in my last post. I see it's 100mΩ giving you good resolution and range with that voltage reference. That's good for sensing, but you're taking a big power hit using a current sense resistor with such a high value.
DCR = 17mOhm for my inductor. too much for you ? It seems reasonable
Like I said before, you seem to be liberal with efficiency. 17mΩ is high, but insignificant compared to other resistive losses in your circuit. The one I'm using is 6mΩ.
Ideally, a device should be able to sit on the shelf for a long period of time without critically discharging the battery. Keep in mind I'm using a non-removable LiPo cell. My worst case is a low battery sitting on the shelf for several months. 10uA provides a generous period of time without without over-discharge. I'm sure there are other ways to handle it, but you also don't want to waste power when the device is idle. That reduces run time. Kills two birds with one stone that way.
The protection is the current shunt if the software CRASH.
That's kind of sketchy. If you have a short and sensing fails, you'll have current limited only by the resistance of the circuit. Being liberal, that's not more than 300mΩ. With a fully charged batt, that's a load of 14A, an over-current condition for an IMR 18650.
With the resistive losses in my design and the ultra-low DCR LiPoly cell, I get a worst case of around 80A with a direct atomizer short. I have to have a fuse. It's not optional.
Why not? [post your design]
I wouldn't be very happy if I posted my whole design to help other DIY modders then found some part of it in a commercial product where someone used the sweat off my back or my ideas to save themselves some work and make a profit. This has happened several times already in this forum. That bothers me a lot. If you don't care about it, that's good for you. That must be the case or you would not have posted your design.
Thank you for your comment.
Thanks again for your replies.