Voltage question

[voofvoof206]

Hi I've been researching ohms law and I'm a little bit confused. When using the equation should you always put 4.2 for the volts if you are using a 4.2 battery and does it always stay 4.2? Like if the battery is at half charge does it fall to 2.1? And if so does that mean it can only handle so low of a resistance versus a fully charged battery?

 

[Baditude]

You always use the voltage of a fully charged battery (4.2 volts). Ohm's Law Calculator

A 0.5 ohm coil will draw 8.4 amps from a fully charged battery at 4.2 volts output.
The same coil will draw 6.8 amps from a drained battery at 3.4 volts output.

Therefore, a battery is most dangerous when fully charged if doing sub-ohm coils.

Another danger is when a battery is over-discharged too quickly (below 3.0 volts), which in of itself may cause the battery to go into thermal runaway. This could be possible if the novice user is not familiar with the signs of the voltage drop of a battery in a mechanical mod.

This is why it is important for novice users of a mechanical mod to have a way to measure their battery voltage while in use.

Omnitester

510 Inline voltage meter

 

[voofvoof206]

Okay thanks man that clears it up a lot for me. You're the best [emoji2]

 

[suspectK]

I use 4.2Volts when finding current needs, and I stay in continuous current ratings.. regardless vaping is a pulse action.

Never allow a battery to reach 2.1volts. Sony VTC's can be discharged down to 2.5Volts, but it's not recommended.

Get an inline voltage meter or multimeter if you don't already have one. You have ~4.1volts measured on a full battery, but under load/resistance connected drawing current, there is voltage loss... always referred to as voltage drop in the vaping world. Heat build up/bad contact resistances and resistance in random parts in the circuit cause voltage loss in mechanical mods.