Who can answer this question???

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tayone415

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After using mechanical mods and rebuilding, I learned a lot especially with batteries and ohms and the way the output works for voltage/watts. Then I started thinking back to when I used regulated variable voltage devices and thought how does that work?

If a battery is a 3.7 volt battery that charges to 4.2 volts +/_ 0.05 volts, how can a variable voltage mod produce 6 volts when on a mechanical mod the voltage continually drops with use?

If I remember too, the lower the battery percent the weaker the hit and vapor was on a regulated device. :confused::confused::confused:
 

Phone Guy

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The chip in a vv/vw device has the ability to regulate the output to what you want. That's kind of the idea behind vv vw devices. Mechs and the right battery & build can output higher "wattage" when the right calculations are done, usually higher than 30w or 50w for the deep sub ohm'ers.....

But its all about the chips in those regulated devices.
 

tayone415

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The chip in a vv/vw device has the ability to regulate the output to what you want. That's kind of the idea behind vv vw devices. Mechs and the right battery & build can output higher "wattage" when the right calculations are done, usually higher than 30w or 50w for the deep sub ohm'ers.....

But its all about the chips in those regulated devices.

I understand the watts on a regulated mod 30 watts or under, and obviously how it works on a mech especially sub-ohming since I never did anything but sub-ohm. I just don't get how a regulated mod can be putting out higher volts than the maximum charge a battery can be at.
 

tayone415

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Because the circuitry contains what is called a buck–boost converter which can produce a range of output voltages much larger (in absolute magnitude) than the input voltage, down to almost zero.

Thanks, I get what makes it work the way it does, don't get how it's able to do that, but I'll just leave it that it's abuck–boost converter .
 

tayone415

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Basically the chip takes in power from the battery and stores it in a capacitor. When the stored energy reaches the potential (voltage) it dumps out to the atty.

DC Boost Converter
Buck-Boost Converter

OK, thanks that makes more sense.

You may want to visit the modding forum if you care to get into a chat about how buck and boost converters work. Modding Forum

I never noticed that section after all this time.

Just seen your banner on your signature, great job. It's really disgusting to see close to how many cigarettes we would of smoked when it's added up for you.
 

readeuler

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Thanks for the answer, Susan. I was wondering this the other day. I suspected capacitors were at play, but my mind glazed over trying to navigate my way through Wikipedia.

I've always wanted to actually learn about electricity/circuits (I think I passed physics II by a slim margin), and vaping has provided the perfect motivation. I even broke out the old textbook a few days ago... Good times.
 

UncleChuck

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A really easy way to think of it is this: The chip pulls in very high current from the battery, and it transforms that extra current into voltage.

Using the water comparison, an APV works similar to taking a 12" water pipe and reducing the end down to 4" which increases the pressure (voltage) of the water.

On a mechanical mod the velocity of the water (voltage) is set and cannot be changed. To get more water (power) at the same speed (voltage) you need a bigger water pipe (low res coils)

On an APV you basically have an adjustable size water pipe, when you turn the voltage or power up your APV increases the size of the water pipe so more water is flowing, then reduces the size down at the end so the speed (voltage) goes up.
 
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