Why do lower ohms give out more vapor?

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MesaMitch

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Hey guys i know it's a stupid question and i've been vaping already for 3 months i should know this already

but Why does lower ohms give out more vapor ??

lets say for example.

i bought a 2.5 ohm Head/coil for a protank
i would vape it at 4.2 volts
i would get average vapor

then lets say i bought
a 1.5 ohm head/coil for my protank
but vaped it at 3.5 volts
why would i get more vapor from the lower ohm?


is it because the coil heats up quicker?

just curious about this guys?

Thanks for any answers i feel stupid even posting this but i am just dying to know why?
 

Lessifer

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The short answer is yes, it's about heat.

2.5ohm at 4.2v is roughly 7 watts, 1.5ohm at 3.5v is a little more than 8 watts. Vapor is about three things, liquid availability(wicking), airflow, and coil temperature(volts/watts/resistance/coil shape). Higher watts(more power) usually results in higher temperature which usually means more vapor, but there are other ways of achieving this without lowering your resistance and upping your voltage.
 

steved5600

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Here is a watts chart and a watts calculator.View attachment wattscalcdhartv1A.xlsxView attachment wattscalcdhartv1.pdf
Most people don't go below 1.3 unless they are doing dual RBA's or RDA's and you have to pretty much use a mech for those as most mods detect that and shut down at like 1.3. I vape at the wattage that just does the job. Go higher and you can burn the juice and it shortens your battery time. I personally never go below 1.3 even with a dual coil. No need to. Vape a big cloud and most of it is not inhaled. Just goes off into the either. LOL
 

Rickajho

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Here is a watts chart and a watts calculator.View attachment 237467View attachment 237468
Most people don't go below 1.3 unless they are doing dual RBA's or RDA's and you have to pretty much use a mech for those as most mods detect that and shut down at like 1.3. I vape at the wattage that just does the job. Go higher and you can burn the juice and it shortens your battery time. I personally never go below 1.3 even with a dual coil. No need to. Vape a big cloud and most of it is not inhaled. Just goes off into the either. LOL

BIG cloud of exhaled vapor = tiny little pns. I think that's what is really going on with the SLR quad coil crowd. Just sayin...
 

vicflo

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Hahaha Steve next coil I make is gonna be dual coil, one at 1ohm and one at 2.5 ohm! Haha! Best of both worlds haha! Like my wonky wick back in the old clearo days... Everyone argued over short or long wick so I cut one wick short and left the other one long haha!

.7 ohms... that is scary. lol
 

UncleChuck

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The short answer is yes, it's about heat.

2.5ohm at 4.2v is roughly 7 watts, 1.5ohm at 3.5v is a little more than 8 watts. Vapor is about three things, liquid availability(wicking), airflow, and coil temperature(volts/watts/resistance/coil shape). Higher watts(more power) usually results in higher temperature which usually means more vapor, but there are other ways of achieving this without lowering your resistance and upping your voltage.

One more very important factor is coil surface area!
 

Discord

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lower ohms alone does not make for more vapor. lower ohms at the same voltage makes the coil get hotter. surface area definitely effects it too, as well as air flow and decent wicking. if any of those are lacking you'll get poor vapor production and possible dry hits. do some reading about microcoils and see how some of the creative coil-winders are producing fantastic results with improved surface area, air flow and wicking without the need for sub-ohm.
 

RedhatPat

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OP: Watts - volts - amps - ohms conversion calculator Heat=Power=V*V/R or in English, heat is power and power, in Watts, is equal to voltage squared divided by resistance in Ohms. For a fixed voltage decreased resistance causes an Increase in heat while increasing the resistance Decreases the heat.

Power formula: P=IV (Power is the product of voltage and current in Amps, sometimes called power law)
V=IR or I=V/R (Current, in Amps, is equal to voltage divided by resistance in Ohms, sometimes called Ohms law)
Substitute the "I" in power law with the "V/R" and you can see where the formula P=V*V/R comes from.
So 4 volts with a 2 Ohm coil is 4*4/2=16/2=8 Watts
And 4 volts with a 3 Ohm coil is 4*4/3=16/3=5.3 Watts

Now with a variable voltage device with an absolute current limit will be able to output more power with a higher Ohm coil, but few devices have an absolute limit and instead use a variable limit that varies with output voltage so it gets rather weird...

HP
 
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