^^^ Most hobby shops carry it. I paid $1 for a foot of it.
I found this on the Atmizoo website under "voltage drop not were you think it is" posted by MANU. Just rewrote it so it was more understandable. And found on Google the internal resistance of aw imr 18650 2000 mah batteries.(that's what I'm using)
How to figure out your Voltage drop
FB / (0.002 + 0.05 + CR) = A
which would give an atomizer voltage of
A x CR = AV
and a wattage of
AV x A = Watts
FB = freshly charged battery voltage
.002 = average internal resistance of a brand new AW IMR 18650 2000 mah Battery
.05 = average internal resistance of a high end mechanical mod
CR = coil resistance
A = Amps
AV = Atomizer Voltage(voltage at the coil)
For example my set up
4.2 / (.002 + .05 + .9) = 4.41 amps
4.41 x .9 = 3.97 AV
3.97 x 4.41 = 17.5 watts
That 3.97 volts should be the voltage measurement at the coil posts (in a perfect world).
Now that I've modded my ZAU and a fresh aw imr battery 4.2 volts I get a measurement of 3.95 volts. The difference in the theory and the actual is negligible. I cant physically make this any better. IT's much much better than the 2.5 volts I was getting before the modification. And for lack of a better saying "It Vapes like a train"
If your math voltage and your actual voltage are much different your mod may have a higher internal resistance, your atty may have a high internal resistance, or you battery is worn a bit causing the internal resistance to be higher
And if there is something wrong with the math let me know I'll fix it.
I found this on the Atmizoo website under "voltage drop not were you think it is" posted by MANU. Just rewrote it so it was more understandable. And found on Google the internal resistance of aw imr 18650 2000 mah batteries.(that's what I'm using)
How to figure out your Voltage drop
FB / (0.002 + 0.05 + CR) = A
which would give an atomizer voltage of
A x CR = AV
and a wattage of
AV x A = Watts
FB = freshly charged battery voltage
.002 = average internal resistance of a brand new AW IMR 18650 2000 mah Battery
.05 = average internal resistance of a high end mechanical mod
CR = coil resistance
A = Amps
AV = Atomizer Voltage(voltage at the coil)
For example my set up
4.2 / (.002 + .05 + .9) = 4.41 amps
4.41 x .9 = 3.97 AV
3.97 x 4.41 = 17.5 watts
That 3.97 volts should be the voltage measurement at the coil posts (in a perfect world).
Now that I've modded my ZAU and a fresh aw imr battery 4.2 volts I get a measurement of 3.95 volts. The difference in the theory and the actual is negligible. I cant physically make this any better. IT's much much better than the 2.5 volts I was getting before the modification. And for lack of a better saying "It Vapes like a train"
If your math voltage and your actual voltage are much different your mod may have a higher internal resistance, your atty may have a high internal resistance, or you battery is worn a bit causing the internal resistance to be higher
And if there is something wrong with the math let me know I'll fix it.
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