Was given, as a bonus, by my b&m, when i bought my TFV4 Mini, both the single and dual build decks. You can garauntee that the dual deck will never see daylight as i only use tc these days and the reasons you list above are exactly why it will never see daylight, i like stress free kiss vapingIMHO: Dual coils have one major impact to TC. Double the connections, twice the potential for hot legs and twice the potential impact of poor wicking. Taken all together, dual coils have 8X more potential to have vaping problems (typically cool vape as results in one wick not keeping up or a hot leg, causing ONE side of the setup to reach temp and shut down the wattage).
I think I figured it out!
If not, then this is at least some brilliant folly.![]()
Coils in parallel, being resistors, will still be seen by an ohm meter (the mod) as a single resistor. To keep the math simple, let's assume they are perfectly identical, 1-ohm coils.
Two 1-ohm coils in parallel create the equivalent of a .5-ohm resistor.
Let's assume they heat and cool mathematically perfect, in perfect unison, and therefore this "variable" resistor (controlled by its temperature) is easier to discuss.
We now have "one" resistor for the mod to analyze hundreds of times a second, as it does. It's looking for a change in resistance.
That change has to be expressed in milliohms, or some such finite unit of granularity. It's looking for so many units of change per unit of time.
A Heating Cycle:
Each increased milliohm that a single, serial wire would report back, is now taking twice the milliohms (for each coil independently) for the circuit as a whole to report back as 1 milliohm of change.
Not a problem for the mod, it will happily push more wattage at it until the heat increases enough in both coils to increase the ohms enough to meet the TCR's delta enough to decide it's reached the target temperature.
A Cooling Cycle:
I think this is where the "magic" happens (the magic of dual coils being anemic).
The power is cut (or reduced) and waiting for the milliohms to drop sufficiently so that it can kick in again.
But just as before, it takes 2 milliohms of change in each coil, to produce 1 milliohm of change for the circuit as a whole.
Since the cooling is a "static" function of the thermodynamics of the coil mass and surface area (and wick), it doesn't have the benefit of a mod to push more cooling at it. It just has to cool at its own natural rate.
The cooling that happens on each coil, independently, is identical in behavior to its single coil counterpart; even when each coil, of a dual, has more wraps, they don't work to retain the heat more, due to the topology of a spiral, spaced coil.
So the cooling cycle is nearly identical between the single build and dual build, but the dual build is required to cool longer, a full 2 milliohms drop in resistance worth of cooling, longer, to report back only 1 milliohm worth of cooling as the mod sees it.
I believe it's this extended cooling cycle, repeated over and over (perhaps dozens or even hundreds of times a second) that results in a net cooler temperature, as compared to the ohm-unhampered single coil build.
The single coil, reports "I'm cooler now," faster.
The dual coil reports "I'm cooler now," slower and therefore, in fact is cooler than the single coil would be, at that reporting.
I think I figured it out!
So the cooling cycle is nearly identical between the single build and dual build, but the dual build is required to cool longer, a full 2 milliohms drop in resistance worth of cooling, longer, to report back only 1 milliohm worth of cooling as the mod sees it.
I would theorize that cooling is faster with dual coils due to the increased volume of cooling liquid in contact with the material. One coil of .1 would have half the wick of two .05 coils.
Do we at least agree that two 1-ohm resistors in parallel read as .5-ohms by an ohm meter (a mod)?
And that if the combined resistors heated up such that they read as 1.5 ohms, that each resistor would have to be 3 ohms (and therefore as hot as 3 ohms)?
And that the reverse of that, as it cools, is also true?
Each individual coil will have a different delta rise and fall compared to the unit as a whole but the TFR would be the same.
So if the unit as a whole was dropping 1 milliohm a microsecond per degree each individual coil would be dropping 2 milliohms a microsecond per degree.
Yes, exactly.
As for the different rise and fall between the two imperfect resistors, that's a detail that is overshadowed by the halving of the combined, read ohms (or nearly halving, because they're not perfect).
E.g.,
Two 1-ohm resistors gives us .5-ohm.
While a 1.1-ohm resistor and .8-ohm resistor gives us .463-ohms.
So, the effect is close enough that an overarching behavior can be pointed to.
Yes to the first sentence. No to the rest.
the actual resistance is...the actual resistance. .
But that's determined by a different set of rules, when looked at under the hood, than its single resistor counterpart.
E.g.,
The single resistor at 2 ohms only has to drop .5 ohms to get to 1.5 ohms.
The dual parallel resistor at 2 ohms must have each of its two resistors, drop a full 1 ohm to get to 1.5 ohms.
If we're talking about the cooling cycle, this is almost twice as long (not quite due to the math involved with heat dissipation, but close enough to point to an effect).
Why twice as long? The dual-coil setup has twice the surface area and wicking as the single coil.
The "anemic vaper syndrome", within the realms of math & physics, points to a physical problem with the atomizer or build, not an inherent issue.
So we agree that two 1-ohm resistors at room temp are halved to .5-ohms, but don't agree that when they're heated to a temp such that they each reach 3-ohms, they'd be read as halved (1.5 ohms) by the mod?
How could this not be true?
I think for the discussion to progress in a meaningful way we need to agree on at least this important point, or explain to me why it's not the case.
But that's determined by a different set of rules, when looked at under the hood, than its single resistor counterpart.
E.g.,
The single resistor at 2 ohms only has to drop .5 ohms to get to 1.5 ohms.
The dual parallel resistor at 2 ohms must have each of its two resistors, drop a full 1 ohm to get to 1.5 ohms.
If we're talking about the cooling cycle, this is almost twice as long (not quite due to the math involved with heat dissipation, but close enough to point to an effect).
What you're missing here is that a dual coil is a single resistor, not two. In your example, put together two 1 ohm coils and they read as .5. It's a .5 resistor. It climbs to 1.5 ohms, not two times 3 ohm. The difference is (if we're dealing with the same gauge wire) that it has more mass and will therefore need more power to heat up and more time to cool down (most likely). But it's a single .5 ohm resistor for all intents and purposes.So we agree that two 1-ohm resistors at room temp are halved to .5-ohms, but don't agree that when they're heated to a temp such that they each reach 3-ohms, they'd be read as halved (1.5 ohms) by the mod?
How could this not be true?
I think for the discussion to progress in a meaningful way we need to agree on at least this important point, or explain to me why it's not the case.
But that's determined by a different set of rules, when looked at under the hood, than its single resistor counterpart.
E.g.,
The single resistor at 2 ohms only has to drop .5 ohms to get to 1.5 ohms.
The dual parallel resistor at 2 ohms must have each of its two resistors, drop a full 1 ohm to get to 1.5 ohms.
If we're talking about the cooling cycle, this is almost twice as long (not quite due to the math involved with heat dissipation, but close enough to point to an effect).
I already explained it. They aren't faking being half the resistance, it's not an arbitrary notion, once in parallel two identical coils ARE half the resistance, and it's ONE circuit. The mod is not applying power to two coils and then dividing the resistance to arrive at a figure, it's applying power to one circuit and reading the actual resistance. You need to grasp this, because it's where your theory fails.
The thermodynamics of varying coil masses doesn't matter either, because the TCR for the material doesn't change. X resistance delta for Y material always equals Z temperature, if it's a single wrap on a single coil, or 100 wraps on 10 coils.
What you're missing here is that a dual coil is a single resistor, not two. In your example, put together two 1 ohm coils and they read as .5. It's a .5 resistor. It climbs to 1.5 ohms, not two times 3 ohm. The difference is (if we're dealing with the same gauge wire) that it has more mass and will therefore need more power to heat up and more time to cool down (most likely). But it's a single .5 ohm resistor for all intents and purposes.
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