I am trying to determine what size wire I need to order so I have everything I need to get started. Being new believe me, it is harder for me to find a way to say it than it is for you to figure out what I am trying to say 
This is how I am doing it, please correct any errors and suggest an easier way if possible.
What I want to do is make the needed dual coils for an IGO-W dripping atomizer (RDA I think). End result I hope to have a 1.3 to 1.8 ohm resistance on the device. If I am reading everything correctly (there is doubt here) then I am looking to make two 3ohm coils to allow myself a little margin for error either way.
Narrow down options....
Kanthal A-1 has the highest resistance per inch so I chose it at 28 gauge for this example.
I have a 2mm drill bit I special ordered and never used so no chuck scaring and will use that as a size base.
The math (not my best subject, was always good at lunch tough) rounded...
Pi x 2mm = 6.28mm so 6.28mm around the drill bit.
28g Kanthal is .32mm thick so the radius is .16mm
.16 x 6.28 = 1.0 adding that to the 6.28 I get 7.28 to find the center of the Kanthal wrap and a closer estimate of length needed for one wrap.
Multiply that by .04 to convert to inches and I get .29, divide 1 by that and find I need to make 3.4 wraps to use an inch of Kanthal A-1 28g @ .46ohm of resistance.
Divide the desired 3.0ohm by .46ohm and find I need 6.5 inches, 6.5 x 3.4 = 22 + or to allow for tails to connect with.
So best guess, 12 wraps would allow me to have two 1/4 inch tails but only produces a 3.4mm wide coil (thickness of two quarters stacked) if the math is correct.
You're asking why I did this the round about way?... because I also want to ensure I have a wide enough coil to contact the most juice.
Am I doing this even close to correct? If so, I assume I will need a smaller gauge wire to cover more area.

This is how I am doing it, please correct any errors and suggest an easier way if possible.
What I want to do is make the needed dual coils for an IGO-W dripping atomizer (RDA I think). End result I hope to have a 1.3 to 1.8 ohm resistance on the device. If I am reading everything correctly (there is doubt here) then I am looking to make two 3ohm coils to allow myself a little margin for error either way.
Narrow down options....
Kanthal A-1 has the highest resistance per inch so I chose it at 28 gauge for this example.
I have a 2mm drill bit I special ordered and never used so no chuck scaring and will use that as a size base.
The math (not my best subject, was always good at lunch tough) rounded...
Pi x 2mm = 6.28mm so 6.28mm around the drill bit.
28g Kanthal is .32mm thick so the radius is .16mm
.16 x 6.28 = 1.0 adding that to the 6.28 I get 7.28 to find the center of the Kanthal wrap and a closer estimate of length needed for one wrap.
Multiply that by .04 to convert to inches and I get .29, divide 1 by that and find I need to make 3.4 wraps to use an inch of Kanthal A-1 28g @ .46ohm of resistance.
Divide the desired 3.0ohm by .46ohm and find I need 6.5 inches, 6.5 x 3.4 = 22 + or to allow for tails to connect with.
So best guess, 12 wraps would allow me to have two 1/4 inch tails but only produces a 3.4mm wide coil (thickness of two quarters stacked) if the math is correct.
You're asking why I did this the round about way?... because I also want to ensure I have a wide enough coil to contact the most juice.
Am I doing this even close to correct? If so, I assume I will need a smaller gauge wire to cover more area.