I agree with Rickajho. It may not make sense, but lower resistance allows more voltage to flow to the coil, so the amperage draw from the battery is more. Higher resistance means their is less voltage going to the coil, thereby less amps used by the battery. At least that's the way I've always understood it. I'm sure dr g will set me right.
Low resistance = more amp draw
high resistance = less amp draw
This is only half of the equation with regulated mods. Because:
There has to be additional current used in the upconvert process though. Taking a 3.7v battery and using a booster to push more volts from the battery requires more power. It doesn't just come from thin air.
The power doesn't come from nowhere, it has to come from the battery at the voltage it supplies. The wattage between the battery supply and the load are the same (disregarding converter losses).
See: http://www.e-cigarette-forum.com/forum/blogs/rader2146/3500-calculating-battery-drain-current.html