ditto on this. There are a few advanced topics that I don't understand when it comes to resistance, voltage and things like number of coils. I'm not an electrical engineer, so that might have something to do with it.
I know there is a lot of information on ECF, but some of the advanced topics like this don't have as much i
So, lower resistance on the same battery will give more vapor, because it's hotter? Yes? How can lower resistance be hotter, wouldn't a higher resistance have more electron collisions, and therefore run hotter? Or is it because it sucks out more amperage, and the velocity of the electrons moving faster create more heat?
How does varying the voltage change the vape experience? I assume the same thing, more voltage = more amps over the same resistance, so therefore more heat. Is that correct?
What about coil numbers. How does having two coils change the vape experience?
Hi there Chry, I used to teach electricity to soldiers a long time ago and at the time I was using this "water hose" comparison to explain volts/amp/and resistance... I'll try to explain here your question about low resistance hotter?
Let pretend that:
Volt is the same as the size of a garden hose, more volts, bigger the hose, ok?
Resistance is like your hand on the tube of the garden hose and the more you squeeze your hand on the hose the more resistance you give it.
Heat (or in our case, coil glow) can be compared to how much water comes out at the end of the hose. (you can ALSO know this as watts)
Now, from here it's easy.
Take 1 inch diameter garden hose (1 volt), open the tap, the water will flow at the end quite good (little resistance from the hose inside = 1 ohms) therefore high heat. Right? Well call this heat 1
Take the same 1 inch hose (1 volt) and squeeze it in the middle about half the size of the hose to create high resistance (5 ohms), therefore less water comes out at the end, less heat. this would be heat 0.2
now, take a 10 inch diameter hose (10 volts) open the tap, the water will flow at the end quite good (little resistance from the hose inside = 1 ohms) therefore high heat. Right? Well call this heat 100
Take the same 10 inch hose (10 volt) and squeeze it in the middle about half the size of the hose to create high resistance (5 ohms), therefore less water comes out at the end, less heat. this would be heat 20.
The formula is really simple.
How do we get from 1 Volt, 1 ohm to 1 watt
or
How do we get from 10 Volts, 5 ohms to 20 watts
easy: multiply volts by itself: 10 x 10 = 100
then divide that by resistance: 100 / 5 = 20
so in the case of our e-cigs, lets see more realistic numbers:
My battery has 2 voltages choice 3.5 volts and 4.0 volts
I have 2 atty heads, one with 1.2 ohms and one with 2.4 ohms.
Lest see what my results would be in some settings possible
my battery at 3.5 volts with 1.2 ohms atty:
3.5 x 3.5 is 12.25
12.25 divided by 1.2 = 10.2 (ish I rounded decimal) Watts
my battery at 3.5 volts with 2.4 ohms atty:
3.5 x 3.5 is 12.25
12.25 divided by 2.4 = 5.1 (ish I rounded decimal) Watts
As you can see, a lower resistance will give you more heat at the same voltage.
My 1.2 ohms atty with my 3.5 volts is 10.2 Watts
if I keep my 1.2 ohms atty and now put the 4.0 volts battery on it:
4.0 x 4.0 = 16
16 divided by 1.2 = 13.3 Watts.
hope you can understand my gribirish...
One thing that I would not want to explain in details, but is good to know, is that with the same coil material, a higher voltage with a resistance that would give you the same watts will fire faster "startup heat"
example:
a 10 volts battery with a 5 ohms atty would give you 20 watts of power
a 100 volts battery with a 500 ohms atty would ALSO give you 20 watts of power, but that red hot coil would be red faster then the lower voltage one.
hope this helps.
cheers
