Bigg Wigg Full Member Sep 6, 2013 6 4 West Des Moines, IA Sep 6, 2013 #1 Sep 6, 2013 Add bookmark #1 So, it's voltage variable from 3.3v to 5.0v. When I charge it, I notice the full charge is 4.2v. How is it getting 5.0v from 4.2v? ••• More options Report Add bookmark Share
So, it's voltage variable from 3.3v to 5.0v. When I charge it, I notice the full charge is 4.2v. How is it getting 5.0v from 4.2v?
xtwosm0kesx Ultra Member ECF Veteran Verified Member Jun 30, 2010 2,298 3,160 Face down in the gutter, USA Sep 6, 2013 #2 Sep 6, 2013 Add bookmark #2 The internal circuitry uses boosters and: Pulse-width modulation - Wikipedia, the free encyclopedia ••• More options Report Add bookmark Share