Just For LM2596 Users

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Java_Az

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What would be the range if the 10k pot was just replaced with a 1k or w/ a 5k?


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If in fact the R1 resistor is 500 ohms a 5K pot would give you 1.5 volts to 13.53 volts . A 1k pot would give you a range of 1.5 volts to 3.69volts .

These modules come in a few different max outputs that i have seen on Ebay. 20 volts 25 volts 35 volts 40 volts. The formula is ( R2 divided by R1 +1 ) then multiply that number by 1.23 and that will give you the high end output voltage. When the pot is dialed to no resistance you get the low voltage of 1.5. Anyways the R1 resistor value is critical in the calculation of the proper value pot. If all the voltages above use a 10k pot the R1 resistor value is going to be different.
 

WillyB

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That usually means it is a Capacitor. There should be a R1 resistor though. The voltage is set by using a voltage divider so there should be a R1 and R2 .
Kinda, but it could very well just be a pot/trimmer using all three leads.

A potentiometer, informally, a pot, in electronics technology is a component, a three-terminal resistor with a sliding contact that forms an adjustable voltage divider. If only two terminals are used, one end and the wiper, it acts as a variable resistor or rheostat.


Here's a typical R1/R2 voltage divider using just a pot.

Dumped all the resistors from the original design and went with only the pot that now is both R1 and R2.

lm_trimmer-_2.jpg
 

Java_Az

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just to add to the above a bit maybe make it easier to understand

We know bj43 's reg has a top end output of 25 volts we also know it has a 10k pot. so we take the formula (R2 divided by R1 +1 ) x 1.23 = output voltage. R2 the Pot is 10000 ohms. If we plug in 500ohms for R1 we have 10000 / 500 = 20 , 20+1 = 21 , 21 x 1.23 = 25.83 output voltage.

Now the lm2596's i am getting have a output max of 35 volts. For the pictures i can also tell they come with a 10k pot. so if i plug in 360ohms for R1 i get , 10000 / 360 = 27.777 , 27.77 + 1 = 28.77 , 28.77 x 1.23 = 35.39 output volts

ok thats enough math for me today, I swear i hear Samual Adams telling me there is a boston lager with his name on it , but assures me it is for me , waiting on me at the beer store .
 

BJ43

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this might not be right still on the first cup of coffee. The max output of that reg is 25 volts ( Voltmeter LED display LM2596 DC-DC step-down adjustable voltage regulator module | eBay)

In order to get a 25 volt output with a 10k trimmer R1 would have to be 500ohms. So there should be a 500 ohm resistor somewhere on that board. Adding a 922 ohm resistor to a 1.2k pot would give you 3.5 volts to 6.5 volts. No such thing as a 1.2 k pot so i would go with a 1 k resistor and a 1k pot . That would give you 3.6-3.7 to 6.15 volts. You could more then likely get closer to your range if the R1 resistor was replaced to a different value. them things are tiny though not sure if you have soldered anything that small before.

These 70 year old fingers don't solder anything smaller than 1/4 inch. lol. Thanks for all the math, cool...
 

CountSmackula

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BJ43

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CountSmackula

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Me too. But... one of my in-laws is giving me lessons. First he lets me muck it up, then he shows me what I should have done, and finally has me do it again myself. I've only got a cheesy Radio Shack pen, while he has a whip-... Hakko soldering station. World of difference. He's keeping an eye out for an old Weller for me on the cheap. Says they'll do pretty much anything I need, and that parts are available for even the old ones.
 

Java_Az

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Not my math it is from the data sheet. Really R1 should be a fixed resistor between 240 ohms and 1.5 k ohms to keep noise out of the feedback pin. At least thats what the data sheet says. But as WillyB pointed out you could run just a pot on the reg.But it should give you the full range of the reg 1.5 to 40 volts. It could also be unstable at certain voltages due to the varying resistance of R1. I am strickly going off the data sheet for my calculations doesnt mean the designer of the circuit did the same thing.

Screenshot-16.png

Screenshot-1-7.png
 

BJ43

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BJ43

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If in fact the R1 resistor is 500 ohms a 5K pot would give you 1.5 volts to 13.53 volts . A 1k pot would give you a range of 1.5 volts to 3.69volts .

These modules come in a few different max outputs that i have seen on Ebay. 20 volts 25 volts 35 volts 40 volts. The formula is ( R2 divided by R1 +1 ) then multiply that number by 1.23 and that will give you the high end output voltage. When the pot is dialed to no resistance you get the low voltage of 1.5. Anyways the R1 resistor value is critical in the calculation of the proper value pot. If all the voltages above use a 10k pot the R1 resistor value is going to be different.

So a 3K pot will give me 1.5 to 8.61 volts, cool.....
 

Java_Az

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So a 3K pot will give me 1.5 to 8.61 volts, cool.....

Should be somewhere around there. But Specs on these chips are not always spot on. I just got a chip today from China ( not the LM2596's they are still not here ) it is supposed to have a adjustable output of 3 to 25 volts. Real life it went from 5 volts to 17.3 volts. Just modified it to go down to 3.2 . So i guess you cant really rely on these sellers to put in the correct specs all the time. Does your chip really go down to 1.5 volts? Since it is a led Model i wouldn't take it over the 25 volts might just fry the LED. I guess really all you can do is slap a 3k pot on that joker and see what she does.
 
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