My modded Reo, part 2 (and final). Results

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dhomes

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I really don't want to drill a hole in my Reo. Would sanding the coating away from where the spring attaches and maybe trying to find a brass hot spring sorta do the same thing?

Robert - is there coating on the inside where the 510 connector is pressed in or do you remove that?

I would think that you would have to follow the current and clear all contact points of the anodizing to maximize the performance difference.

Please correct me if I"m wrong...I'm learning.

not the SAME thing, but it will improve it some .2 to .3 Volts

Sand the are below the hotspring, and certainly a brass hotspring will work better (if there are any, not aware)

also, a thicker screw connecting the hotspring will help as well, it's a matter of widening a bit the hole you already have

And if you were to put a small washer & nut, and tight real well, you would get even better results
 

dhomes

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Do you think changing the battery contact point from a point to more of a longer flat area would help with reducing drop as well?

Maybe, the custom bar I have is just as pointy as the real one, I actually told the guys to make it about 1 or 2 mm flat at the tip but he gave me a perfect copy at the tip
 

dhomes

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..........

If you read the whole thread, the biggest improvement comes from the negative connection

A good thing about Silver (as I mentioned before) is that it does not oxidize (at least, nowhere as much as aluminum) so filing & noalox shouldn't be necessary

I said nearly as much as mine is 99.25% Silver, .75% copper

But I can buy 99.999999% silver on my own (at a greater cost) and have these done -> this shouldn't oxidize pretty much at all
 
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dhomes

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I would think that you would have to follow the current and clear all contact points of the anodizing to maximize the performance difference.

Please correct me if I"m wrong...I'm learning.

The more continuity (less contacts points), better conductive material & contact area you can provide the better!
 

dhomes

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Just yesterday I was thinking about making a one of a kind clone for myself with the body made out of 99.99999% silver

not for selling, it would be utterly expensive & I have no plans for selling mods

But that would be quite interesting to have, i could make it with only two contacts points (1 at the positive & 1 at the negative of the battery)
 

dhomes

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GUYS, BEFORE IT GETS OUT OF HAND, DO NOT PLAY WITH THE HOTSPRING

if you want to sand the paint below the paint, that's fine

if you want to replace the stock screw with a brass on at the same location, that's fine too

but for your own security, DO NOT leave it without a hotspring

anything you do at the top is safe, the collapsing mechanism is at the bottom / negative connection

What I did I did because I have a high disregard for my face

I wanted to express this before it got out of hand
 

SeaNap

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Wow, 5 bucks! This is some very interesting stuff. Increasing the conductivity, and therefore reducing the voltage drop, does not just help modders vape ridiculous watts, but it can help everybody. I did some math the other day and I found that if you maintain a specific wattage and you increase both the resistance and the voltage you will actually decrease the current draw. What that means is that by being able to maintain a higher voltage, we can use higher ohm coils, and increase the life of our battery.

10watts = 3.7V^2 / 1.37ohm using V=IR the Current comes out to 2.7A

10watts = 3.85V^2 / 1.48ohm using V=IR the new Current comes out to 2.6A

Thats a 4% reduction in current draw by only increasing the voltage by 0.15V and the resistance by 0.11ohm. The more dramatic the voltage and resistance increase the less current drawn.

Sorry for boring you with the maths, or if this has already been covered and im just late to the game. Keep up the good work experimenting with increasing the conductivity!
 

SeaNap

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dhomes ever consider putting a fuse in your circuit to protect your face and battery? I found a "very fast blow" 20A fuse from Littlefuse, that is very small (10mm x 3mm), and has very low resistance (0.0023ohm @ 2A)

0456020. Fuses - Littelfuse

(I am no way affiliated w/ littlefuse that particular fuse happened to meet the specs)
 

dhomes

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Wow, 5 bucks! This is some very interesting stuff. Increasing the conductivity, and therefore reducing the voltage drop, does not just help modders vape ridiculous watts, but it can help everybody. I did some math the other day and I found that if you maintain a specific wattage and you increase both the resistance and the voltage you will actually decrease the current draw. What that means is that by being able to maintain a higher voltage, we can use higher ohm coils, and increase the life of our battery.

10watts = 3.7V^2 / 1.37ohm using V=IR the Current comes out to 2.7A

10watts = 3.85V^2 / 1.48ohm using V=IR the new Current comes out to 2.6A

Thats a 4% reduction in current draw by only increasing the voltage by 0.15V and the resistance by 0.11ohm. The more dramatic the voltage and resistance increase the less current drawn.

Sorry for boring you with the maths, or if this has already been covered and im just late to the game. Keep up the good work experimenting with increasing the conductivity!


SeaNap, I will for sure get a few 20Amps fuses, all the ones I was aware of werer the 10 Amp kind

And yeah, I found that after a day of vaping on a 2200 mAh Panasonic battery with a .7 ohm coil and checking every two hours my battery still has 3.72 volts left

it used to take 6 hours to get there, i vape 7 to 10 ml a day!
 

dhomes

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Mar 20, 2012
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Wow, 5 bucks! This is some very interesting stuff. Increasing the conductivity, and therefore reducing the voltage drop, does not just help modders vape ridiculous watts, but it can help everybody. I did some math the other day and I found that if you maintain a specific wattage and you increase both the resistance and the voltage you will actually decrease the current draw. What that means is that by being able to maintain a higher voltage, we can use higher ohm coils, and increase the life of our battery.

10watts = 3.7V^2 / 1.37ohm using V=IR the Current comes out to 2.7A

10watts = 3.85V^2 / 1.48ohm using V=IR the new Current comes out to 2.6A

Thats a 4% reduction in current draw by only increasing the voltage by 0.15V and the resistance by 0.11ohm. The more dramatic the voltage and resistance increase the less current drawn.

Sorry for boring you with the maths, or if this has already been covered and im just late to the game. Keep up the good work experimenting with increasing the conductivity!


btw, note that on a .7 ohm (what I normally use) from my last video, I'm reaching 3.99/3.98 volts
 

dhomes

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dhomes,

IF I throw out my spring and put in a bolt will I get a heavy beard like you have. My man lawn would have severe beard envy if there was a contest.

Have fun modding. Its a good spectator sport for me.

he he he, I'm of Lebanese-German descent, hair grows pretty fast and I can't get past shaving once a week
 
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