Need help to grasp current (Amps)

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Vaping_Racoon

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Hi guys,

so I'm looking at my calculator and I'm wondering about how the current works.

Let's say I have a Dual Parallel 0.2 ohms build, the calculator says:

Based on 3.7[V] - Current 18.5 [A] - Power 68.5 [W]

So.. if I have 2 batteries rated at 20 Amps, I should be safe if the current drawn is
18.5 [A] ?

What happens if a build goes over 20 [A] ?

lol, thanks for helping me understand.
 

fenderstrat

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ok ,in a regulated mod the build means NOTHING,the mod does what it need to to fire as long as the ohms are within the firing limits of the device its good.since you are running 2 batts in series you can use 7.4V as an average V.Take whatever watts you set your device at and divide by the V and this gives you an estimated AMP draw.Now there are variables like device efficiency and such but you can get an idea
for example if you set a device to 50W 50/7.4V =6.75Amps
most guys use the min volts to get what your max amp draw will be so using that 50watts/6.4(3.2V per batt)=7.4amps
 

beckdg

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ok ,in a regulated mod the build means NOTHING,the mod does what it need to to fire as long as the ohms are within the firing limits of the device its good.since you are running 2 batts in series you can use 7.4V as an average V.Take whatever watts you set your device at and divide by the V and this gives you an estimated AMP draw.Now there are variables like device efficiency and such but you can get an idea
for example if you set a device to 50W 50/7.4V =6.75Amps
most guys use the min volts to get what your max amp draw will be so using that 50watts/6.4(3.2V per batt)=7.4amps
Exactly

But be sure to always use 6.4 to 6.0 volts and your wattage setting to calculate your max amps.

The device is going to pull what it needs from the battery no matter the charge state, so the highest current will be drawn just before the batteries capacity is depleted.

This will keep you within the limits of your batteries.

Tapatyped
 

fenderstrat

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low builds ARE very dangerous on a MECH mod as there is no control and a battery can be taxed till it vents.A reg mod simply wont fire
I dont know of any recent regulated mod that will let you do dmage to the batts.there are numerous protections in place.
Yes I'm sure someone could do it but under normal vaping conditions regulated mods are pretty safe. just remember Watts div by Volts = Amps you can multply by .9 if you want but you get the idea
 
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MMcQ

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That is some serious magic going on in these regulated boxes as according to that theory one should be able to put two 10 amps panny's in there and still get up to 50 watts. My kbox 120 says to only use 30 amp batteries (only got 20's:() but i never go below 1.1 ohms and 20 watts so i'm just gonna risk it at this point. Thoughts?
 
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bwh79

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Regulated and Series.
Amp draw on a regulated device is related only to the wattage setting and remaining battery voltage, with the ideal formula:

Amps = Watts / Volts

You can then divide that result by the device's efficiency, or just use 90% (.9) if you aren't sure, for a total draw of:

Amps = (Watts/Volts) / .9

Note that atomizer resistance does not play a part in this equation.

Amp draw will be highest when the batteries are at their lowest charge, so when doing safety calculations you should use your device's low-voltage cutoff point, or if you don't know that value, you can use 3.2v per battery as a rough estimate. Batteries wired in series add their voltages together, so for a dual-battery device you're looking at 6.4v cutoff.

It's a good idea to leave yourself a good margin for error of at least 20%, which means you would not want to push a 20A battery any harder than 16 amps. Plugging in all these numbers together, we are looking at:

16 = (Watts/6.4) / .9

Rearranging a little we get:

16 * .9 = Watts / 6.4
16 * .9 * 6.4 = Watts
... = 92.16

You should be good with those batteries up to 92.1 watts.

Check: 92.1 watts / 6.4 volts / .9 efficiency = 15.989 amps

Some people prefer to leave a larger safety margin, sometimes as high as 50%. Others will be more comfortable pushing the limits, and might go as high as 100 or 120 watts on those batteries, but I wouldn't recommend that until you have significantly more knowledge and experience.
 

Topwater Elvis

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Even using a regulated power device you still must choose appropriate batteries for your intended power range.

There is no saftey / protection feature that prevents the use of the wrong chemistry or insufficient CDR battery(s).

30w / 3.2v = 9.37a
40w / 3.2v = 12.5a
A 10a cell aint gonna cut it in the above examples.
Safety conscience vapers leave a % of amps under any battery’s CDR as a safety margin/headroom.
Some folks 20%, others 50% under the CDR.
 
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fenderstrat

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ok now I'm really going to $#@# up the works.
all this talk about Amp draw uses the CDR and we usually pulse our mods the problem is there is almost no info on what a "pulse" is on an 18650..lol..but its safe to say the pulse rating is almost always higher than the CDR so if its a 20 amp cdr batt and you are pulsing 25 amps you should be ok...but that is something I dont recommend unless you are fully aware of all conditions and you do so fully at your own risk
 

MMcQ

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Even using a regulated power device you still must choose appropriate batteries for your intended power range.

There is no saftey / protection feature that prevents the use of the wrong chemistry or insufficient CDR battery(s).

30w / 3.2v = 9.37a
40w / 3.2v = 12.5a
A 10a cell aint gonna cut it in the above examples.
OP was talking about a Series mod with 2 batt's. That's a single battery equation.
 
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