Need some basic electrical understanding.

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Battletroll

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Dec 28, 2011
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I do ave an electrical background although not to te component level just to the box level. Military avionics type so my basic electrical knowledge that was taught to e years ago has faded since Im mainly concerned with wiring if I have voltage or not and good grounds.

I'm trying to make a mod from scratch and I'm getting myself wrapped around these things.

1. Voltage - the higher the voltage the harder the hit off your mod

2. Current - I believe this is where I am getting confused.
I have seen a lot of post talking about mAH needing to be high in order to have a good e cig but doesn't this have more to do with how long the battery will last before needing a recharge or swap out?

I have also seen people talk about the amps needing to be around 2.5A to 3.0A in order to have a good e cig. When people are saying this are the really talking about the mAH again so 2.5 A = 2500 mAH?

So if this is the most important thing then we are limited within our capabilities on battery manufactures?

To help me understand better what formulas should I be using when considering a battery and my mod? I started with an ego cig and used it for about two weeks but wasn't getting the hit I wanted (mAH?) I believe the voltage is 3.7 VDC and was the 600 mAH battery. I picked up a veriable voltage (cylon from electronicstix) and I believe it is an 18650 unprotected and I have it set at 4.6 VDC for most my juices. What are the mAH at the setting with a standard carto? What is that formula, I'm brain farting on how to figure it out.

I know a lot of questions sorry but want to understand this so I can build a mod that works. Thank you in advanced for all your assistance.

P.S. I know what I want to do when I grow up. I bought a bread board and have been playing with circuits. I migh like engineering but boy do I suck at math and formulas. Do you think 40 is to old to start?
 

9ball_AJ

On the Snap...
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Verified Member
Let me see if I can help a little bit here:

1. Voltage - the higher the voltage the harder the hit off your mod - Not necessarily, Watts is what makes the hit "harder". Power(Watts) = Voltage(Volts) x Current(Amps) (P=EI). Higher Voltage coupled with higher resistance can still give you a similar wattage as lower voltage with lower resistance.

2. Current - I believe this is where I am getting confused. - Current is a measure of electrons, IOW Volume of electricity.
I have seen a lot of post talking about mAH needing to be high in order to have a good e cig but doesn't this have more to do with how long the battery will last before needing a recharge or swap out? mAh (milli amp hours) is a measure of the capacity of the battery that correlates to how long the battery will last at a given wattage. See this article. However low mAh batteries cannot deliver the amperage needed to fire some lower resistance coils. This is why it is not recommended to use low resistance coils on mini and super mini ecigs. Regulated devices have a chip that shuts the unit down if a certain amperage is exceeded (safety feature), and on some devices the MOSFET switch is rated to handle a certain amperage and can be damaged if the amperage is too high.

I have also seen people talk about the amps needing to be around 2.5A to 3.0A in order to have a good e cig. When people are saying this are the really talking about the mAH again so 2.5 A = 2500 mAH? - Not Really, Amps and Amp Hours are not the same thing. Amps are a measure of how many electrons are flowing, and Amp hours is a rating given to batteries to help determine how long tehy can deliver a certain amount of amps.

Do a google search for Ohm's Law Calculator (here is one), and you can put in certain values and it will calculate other values. For example on your eGo: I believe it is regulated to 3.4V, and if you are using a Boge 2.0 Ohm Carto you are using 1.7Amps of current to fire the coil resulting in 5.78 watts of power. I have heard that 9-10 watts is the sweet spot, but this is subjective and differs with different juices. So to generate 10 watts with your 4.6v example you would need to use a 2.116 Ohm carto or atty or whatever.

The mAh rating of the battery only determines how long the battery will last. See this post for an example of 3 differently rated 18650 batteries and their discharge properties.

If I am incorrect about any of this, feel free to correct me or fill in any gaps.

I hope this helps.

-AJ

I do ave an electrical background although not to te component level just to the box level. Military avionics type so my basic electrical knowledge that was taught to e years ago has faded since Im mainly concerned with wiring if I have voltage or not and good grounds.

I'm trying to make a mod from scratch and I'm getting myself wrapped around these things.

1. Voltage - the higher the voltage the harder the hit off your mod

2. Current - I believe this is where I am getting confused.
I have seen a lot of post talking about mAH needing to be high in order to have a good e cig but doesn't this have more to do with how long the battery will last before needing a recharge or swap out?

I have also seen people talk about the amps needing to be around 2.5A to 3.0A in order to have a good e cig. When people are saying this are the really talking about the mAH again so 2.5 A = 2500 mAH?

So if this is the most important thing then we are limited within our capabilities on battery manufactures?

To help me understand better what formulas should I be using when considering a battery and my mod? I started with an ego cig and used it for about two weeks but wasn't getting the hit I wanted (mAH?) I believe the voltage is 3.7 VDC and was the 600 mAH battery. I picked up a veriable voltage (cylon from electronicstix) and I believe it is an 18650 unprotected and I have it set at 4.6 VDC for most my juices. What are the mAH at the setting with a standard carto? What is that formula, I'm brain farting on how to figure it out.

I know a lot of questions sorry but want to understand this so I can build a mod that works. Thank you in advanced for all your assistance.

P.S. I know what I want to do when I grow up. I bought a bread board and have been playing with circuits. I migh like engineering but boy do I suck at math and formulas. Do you think 40 is to old to start?
 

djej

Senior Member
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Dec 26, 2011
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What about dual coil cartomizers?

Let's say you have 4 volts going to a carto. One carto is 2ohm single coil, the other is 2ohm dual coil. Which gets hotter? Same resistance, so same load on battery, right?

But whats the real difference in heating ONE 2 ohm coil, vs TWO 4 ohm coils? Do the TWO 4 ohm coils get half as hot each since they are twice as resistant in themselves? Or does the wiring in series of these coils allow them to both get as hot? Would ONE 4 ohm coil be half as hot as ONE 2 ohm coil (this of course is different resistances, but still assuming the 4volt delivery as the bassline).

This has always confused me. I keep reading that you can run dual coils at a higher voltage without a burning taste, because of the increased surface area of the coils (there's two of them). BUT...I'm assuming it's not a burning taste because each coil is not getting as hot. Maybe it's all directly proportional, and the 2 coils of a dual coil are equal in heat to the 1 coil of the single coil (once again, assuming same resistance between the two).

:blink::blink:
 
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zoiDman

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SiBurning

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Apr 29, 2011
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What about dual coil cartomizers?

Let's say you have 4 volts going to a carto. One carto is 2ohm single coil, the other is 2ohm dual coil. Which gets hotter? Same resistance, so same load on battery, right?

But whats the real difference in heating ONE 2 ohm coil, vs TWO 4 ohm coils? Do the TWO 4 ohm coils get half as hot each since they are twice as resistant in themselves? Or does the wiring in series of these coils allow them to both get as hot? Would ONE 4 ohm coil be half as hot as ONE 2 ohm coil (this of course is different resistances, but still assuming the 4volt delivery as the bassline).

This has always confused me. I keep reading that you can run dual coils at a higher voltage without a burning taste, because of the increased surface area of the coils (there's two of them). BUT...I'm assuming it's not a burning taste because each coil is not getting as hot. Maybe it's all directly proportional, and the 2 coils of a dual coil are equal in heat to the 1 coil of the single coil (once again, assuming same resistance between the two).

:blink::blink:
Those two 4 ohm coils would be wired in parallel to match a 2 ohm carto, and that means each gets half the current coming from the battery.

I don't have any answers, but Is this the reason that people prefer HV vaping? discusses some of the factors. My post in there goes off on a tangent about some physical factors besides Mr. Ohm's law. I was hoping people would pick up on it (or even pick on me) but... Anyway, it seems like we're asking some of the same questions.
 
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