Question about resistors

[vapn]

I am wondering how the resistor works. Does it drop the voltage down 1v or does it keep the voltage at 5v no matter what battery you use. If you put two 3.7v batteries in the Prodigy (w/ resistor) what voltage are you actually running? 6.4 or 5?

Hopefully I can get an answer from Cash on this..

 

[Johnny 5]

I believe it drops the voltage by a certain percentage.

 

[vapn]

Did I mention how much I love 5v vaping? I just received a new mod today that runs at 6v. I do not like that at all... Do not... It tastes burnt way to quick. Cash you know what you are doing... The Prodigy is the TOP DOG!@! I have been using the 801 for a few weeks now and before that it was the 901. I got an adaptor today to use the 510 at 5v and that is my new favorite. That's a nice vape. Big hits with a short drag and good flavor. No burning.

 

[CaSHMeRe]

A resistor drops voltage no matter what you throw at it ... The higher amount of voltage fed to the resistor, the more it drops, and vice versa ...

We use a .5ohm 2watt resistor in the Prodigy. It drops the loaded voltage from 5.7v to roughly 4.75v - 5.0v ... If you were to use 3.7v batteries, I could only assume you would see a loaded voltage of around 7.0v - 7.1v (assuming batts are charged and showing 8.4v at the adapter) With resistor in place, you would probably see around 6.3 - 6.4v ... Again ... Only a guess since I don't have any 3.7v batteries to test ...

 

[vapn]

That's what I would think too. Thanks for the info.

Did I happen to mention how much I like 5v vaping? lol...

O and I want an anodized Prodigy...lol... Red... I might just do this myself to be different. Buff the heck out of it after I remove the Powder coat anyway then anodize it red... yea red...