Mooch said in video 3 of minding your mahs that we still need to calculate thingsThe mod could be either parallel or series with the batteries. As it is a regulated mod you don't need to do calculations for it.
I totally get that, what I’m questioning is, can I use ohms law to see my watts that my mech is using, and then set my regulated device to that wattage with the same atty and build and get the same vape experience? From my understanding you are telling me yes I can, but my concern is weather the fact that the regulated is series makes a difference or plays a role at all in me setting that afore mentioned wattsWether it's regulated or unregulated watts is watts. The maths is different for both though.
With an unregulated series mod yes you calculate using 8.4 volts.
With a regulated mod series or parallel doesn't matter to the user as it's on the battery side of the regulator chip. The chip draws on this combined pool of voltage to provide the requested wattage on the coil side of the chip. Series is usually used in multi-battery regulated mods as it more efficient.
So, calculate the amp draw using 4.2 volts, then divide by the number of batteries for your amp draw per battery. Then calculate again for 3.2 volts as the amp draw will be highest at this point.
Read this -
sonicbomb's blog | E-Cigarette Forum
or
Calculating battery current draw for a regulated mod | E-Cigarette Forum
In principle yes. Mechs are less efficient, so factor that in when doing your initial rough calculations. I would knock off about 20% to allow for battery voltage sag and losses in the mod.
Then go by what your mouth and lungs are telling you.
Ultimately it's difficult to directly compare the two as they are different, but you can get in the right ballpark using ohms law.
Wether it's regulated or unregulated watts is watts. The maths is different for both though.
With an unregulated series mod yes you calculate using 8.4 volts.
With a regulated mod series or parallel doesn't matter to the user as it's on the battery side of the regulator chip. The chip draws on this combined pool of voltage to provide the requested wattage on the coil side of the chip. Series is usually used in multi-battery regulated mods as it more efficient.
So, calculate the amp draw using 4.2 volts, then divide by the number of batteries for your amp draw per battery. Then calculate again for 3.2 volts as the amp draw will be highest at this point.
Read this -
sonicbomb's blog | E-Cigarette Forum
or
Calculating battery current draw for a regulated mod | E-Cigarette Forum[/QUOTE
I’ve never seen Sonicbooms blog. That was interesting. Thanks for the link. Always more to learn with vaping!
Can you Explain these calculations for me in a little more detail please, using example numbers? It would be a great helpWether it's regulated or unregulated watts is watts. The maths is different for both though.
With an unregulated series mod yes you calculate using 8.4 volts.
With a regulated mod series or parallel doesn't matter to the user as it's on the battery side of the regulator chip. The chip draws on this combined pool of voltage to provide the requested wattage on the coil side of the chip. Series is usually used in multi-battery regulated mods as it more efficient.
So, calculate the amp draw using 4.2 volts, then divide by the number of batteries for your amp draw per battery. Then calculate again for 3.2 volts as the amp draw will be highest at this point.
Read this -
sonicbomb's blog | E-Cigarette Forum
or
Calculating battery current draw for a regulated mod | E-Cigarette Forum