No. It should be the other way around. Less wraps should be hotter. Lesser the wraps, the lesser the resistance. We can derive the following from Ohm's law:
Code:
Watts = Volts X Volts / Ohms
Amps = Volts / Ohms
So using these simple formulae and keeping the voltage constant at 3.7V, you get(P = power in watts, I = current in Amps and R = Resistance in ohms)
- R = 1.0 ==> I = 3.7 and P = 13.7
- R = 1.5 ==> I = 2.5 and P = 9.1
- R = 2.0 ==> I = 1.8 and P = 6.8
- R = 2.5 ==> I = 1.5 and P = 5.5
As you can see the power and current used decreases as you increase the resistance at constant voltage which is what a non VV like iHybrid will provide straight out of the battery. The higher the wattage and current, the hotter the temperature to evaporate the e-liquid generating more vapor and hotter vape as well.
Finally, something I can contribute to this thread.