Vaping at high voltage - myth or fact?

[BadHabit]

The reason juice vaporizes in the first place is that the coil heats it. The temperature of the coil depends on the on the amount of current flow. That is determined by the relationship between the resistance and voltage. E-cigarettes may be new (last 6 years or so) but this technology is as old as Edison and Bell.

Regardless of whether you vape at 3.2v, 3.7, 5v, or 6v, if you use a coil with a resistance value that heats your coil to your sweet spot, why is vaping at any one voltage any better than another voltage? If your sweet spot comes at 320 Deg C, what difference does it make whether you attain that temperature at 3.2v or at 6+? You could conceivably vape at AC for that matter.

The juice doesn't know how many volts you are vaping at. It only cares about temperature. Hot does not necessarily mean HV.

Not knocking HV vaping, just curious why people vape up there. Length of usage between charges?

Happy Holidays!

 

[SiBurning]

The temperature is more related to power dissipated by the resistor, which is the square of current: P=i*i*R=v*v/R=i*v. The math shows how you get more power from increasing current (or voltage) than by decreasing resistance. There's a bunch of other factors such as heat capacity and contact surface area, but they're probably less important for a first pass. Where they do come into play is that these things determine the rate of heat transfer from the wire to the liquid. Basically, the wire coverts electric energy into heat, which is absorbed by the liquid to heat it and convert it from liquid to gas. The rate of heat flow is determined partly by the temperature difference between the wire and the liquid, so temperature matters, but it's not entirely straightforward. A wire of a different material or a different geometry could produce the same heat transference at a different temperature, or vice verse. I think you're also on the right track talking about longevity, but that's just part of the geometry. Higher voltage allows higher resistance (not in direct proportion), which basically means more wire, which means more contact surface with the liquid, more vapor, etc. Finally, as a practical matter, to get equal power out of lower voltages means pulling more current out of the batteries, which they might not like as much.

 

[Kind Head]

The temperature is more related to power dissipated by the resistor, which is the square of current: P=i*i*R=v*v/R=i*v. The math shows how you get more power from increasing current (or voltage) than by decreasing resistance. There's a bunch of other factors such as heat capacity and contact surface area, but they're probably less important for a first pass. Where they do come into play is that these things determine the rate of heat transfer from the wire to the liquid. Basically, the wire coverts electric energy into heat, which is absorbed by the liquid to heat it and convert it from liquid to gas. The rate of heat flow is determined partly by the temperature difference between the wire and the liquid, so temperature matters, but it's not entirely straightforward. A wire of a different material or a different geometry could produce the same heat transference at a different temperature, or vice verse. I think you're also on the right track talking about longevity, but that's just part of the geometry. Higher voltage allows higher resistance (not in direct proportion), which basically means more wire, which means more contact surface with the liquid, more vapor, etc. Finally, as a practical matter, to get equal power out of lower voltages means pulling more current out of the batteries, which they might not like as much.

I learn something new here @ ECF everyday. Thanks for breaking that down.

What is considered HV anyway? I just ordered a 5V mod. Is 5V high V?