Ok i think im confusing myself. This isn't adding up. Is there something I'm missing? Is the 950 mah not part of the calculation? Someone clue me in.
Try working it "backwards" starting with amperage (since that is usually the limiting factor).
If you have a limit of 950ma thru a 3 ohm resistance, it will drop 2.85V and dissipate 2.70W as heat. If you throw 5V on it, your battery is liable to become quite cross.
If you have alimit of 2A thru a 3 ohm resistance, it will drop 6V and dissipate 12W as heat, providing you fed it 6V to begin with.
A battery as used in an e-cig is pretty much a "constant current" power supply when used @ max output. Consider the current limitations first.